Panel surface area =34m×46m=1,564m^2
total power =1564m^2×1390w/m^2
=2173960watts
now you must calculate total energy.
Energy = power×Time
However time must be in seconds so we multiply 2hrs×60min×60s=7200seconds
7200s×2173960w =15,652,512,000 joules of energy
Answer:
(D) Vega must produce more energy than HR 4374.
Explanation:
The apparent visual magnitude is defined as the luminosity of a star seen from earth. The Greek astronomer Hipparcos was the first who invent a numerical scale to describe how bright a star appear to be in the sky to the naked eye, so he gave an apparent magnitude of 6 to the faintest star in the sky and an apparent magnitude of 1 to the brigthest one. Since the arrive of the telescope era this range was expanded to negative numbers for the most luminous one.
The human eye has a logaritmical response to the luminosity of stars, so as an example, if one star has an apparent magnitude of 6 and another one has an apparent magnitude of 1, the second one will be 100 times brigther than the first one. In the other hand, for a star that has apparent magnitude of 1 it will appear to be 2.512 times brigther than a star with apparent magnitude of 2.
The apparent magnitude of a star can variate as a consecuence of the distance from earth or for its energy production.
With all these facts clear enough described above, it is easier to conclude that as the two star are at the same distance the apparent visual magnitude will depend in the energy production. In the case of Vega it has an apparent visual magnitude of 0.03, while HR 4374 has an apparent visual magnitude of 4.87. According with the scale stablished for Hipparcos, Vega will be more luminous than HR 4374. This means that Vega produce more energy than HR 4374.
Some guidance notes which may help.To calculate the current flow, Ohm's law can be used. This can be written as current=voltage/resistance, or I=V/R. V is 1.5V.R for the copper wire quoted would be calculated as R = resistivity x length/cross sectional area. The area would be calculated from the formula area = pi x diameter squared/4So, R=resistivity x length divided by (pi x diameter squared/4)Until is the resistivity of copper is known, that's about as far as can be gone.Any further questions, please ask.
Answer:
What part of the light wave is related to the brightness of the light?
Amplitude
The amplitude of a wave tells us about the intensity or brightness of the light relative to other light waves of the same wavelength
The brightness of light is related to intensity or the amount of light an object emits or reflects. Brightness depends on light wave amplitude, the height of light waves. Brightness is also somewhat influenced by wavelength.
<u><em>Answer</em></u>
A) 1,347.5 Joules
B) 22.49 m/s
<u><em>Explanation</em></u>
<u>Part A</u>
The work done by the gravity is known as potential energy.
It is given by;
P.E = mgh
Where m is mass, g is acceleration due to gravity and h is the vertical height.
P.E = 5.5 × 9.8 ×25
= 1,347.5 Joules.
<u>Part B</u>
Using the Newton's third Law of motion,
V² = U² +2as
Where v is final velocity, u is the initial velocity, and s is the displacement of the stone.
V² = 4² + (2×9.8×25)
= 16 + 490
= 506
V = √506
= 22.49 m/s
