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rodikova [14]
3 years ago
14

-3x^2+ 3 What is the difference quotient

Mathematics
1 answer:
Serggg [28]3 years ago
3 0

Answer:

-6x - 3h

Step-by-step explanation:

Write as a function.

f(x)=-3x^{2}+3

Consider the difference quotient formula.

\frac{f(x+h)-f(x)}{h}

Find the components of the definition.

f(x+h)=-3h^{2}-6hx-3x^{2}+3\\f(x)=-3x^{2}+3

Plug in the components.

\frac{f(x+h)-f(x)}{h}=\frac{f(x+h)=-3h^{2}-6hx-3x^{2}+3}{h}

Simplify

\frac{3h(-h-2x)}{h}

-6x - 3h

<em>good luck, i hope this helps :)</em>

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8 0
3 years ago
Given g(x) = 1/2x+ 5, find the following.<br><br> g(4)<br> g(-10)<br> g(0)
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Answer:

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Step-by-step explanation:

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6 0
4 years ago
Rhea got a new e-scooter. She wanted to show it to her friend on the way to the library.Her friend ronan's house is due north of
Zepler [3.9K]

The distance between rhea and her friend's house could be 8 km and The distance of the library from the rocks house could be 15 km.

<h3>What is Pythagoras' Theorem?</h3>

If ABC is a triangle with AC as the hypotenuse and angle B with 90 degrees then we have:

|AC|^2 = |AB|^2 + |BC|^2    

where |AB| = length of line segment AB. (AB and BC are rest of the two sides of that triangle ABC, AC being the hypotenuse).

rhea got a new e-scooter. She wanted to show it to her friend on the way to the library.

Her friend Ronan's house is due north of her house.

After showing him the new scooter she went to the library which is due west from rocks house.

while returning back she drove 17km diagonally to her house.

By Pythagoras' theorem

|AC|^2 = |AB|^2 + |BC|^2    

Here we can assume that

AB = The distance between rhea and her friend's house.

BC = The distance of the library from rocks house.

The triplet of the 17 would be (8, 15, 17)

So, we can say that the AB could be 8 km and BC could be 15 km or vice versa.

Learn more about Pythagoras' theorem here:

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7 0
2 years ago
What is an equation of a circle with center (2,7) and radius 4?
goblinko [34]

Equation of a circle:

(x - h)^2 + (y - k)^2 = r^2


In this case:

<span>center (2,7) and radius 4 so h = 2, k = 7 and r = 4

</span>Equation:

(x - 2)^2 + (y - 7)^2 = 4^2

(x - 2)^2 + (y - 7)^2 = 16


Hope it helps.

8 0
4 years ago
Una recta que pasa por los puntos A (2,1) y B (6,3) y otra recta pasa por A y por el punto (0,y) ¿Cuánto vale y, si ambas rectas
ASHA 777 [7]

The translation of the question given is

A line that passes through the points A (2,1) and B (6,3) and another line passes through A and through the point (0, y). What is y worth, if both lines are perpendicular?

Answer:

y = 5

Step-by-step explanation:

Line 1 that passes through A (2,1) and B (6,3)  

Slope (m1) = 3-1/6-2 = 2/4 = 1/2

y - 1 = \frac{1}{2} ( x -2)

2y - 2 = x- 2

y = \frac{x}{2}

Line 2 passes through A (2,1) and (0,y)

slope (m2) =\frac{y-1}{-2}

Line 1 and Line 2  are perpendicular

m1*m2 = -1

\frac{1}{2}  * \frac{y-1}{-2} = -1

y-1 = 4

y = 5

slope = -2

Equation of Line 2

Y-1 = -2(x-2)

y -1 = -2x +4

2x +y = 5

7 0
3 years ago
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