Answer:
15.24 square meters
Step-by-step explanation:
Signal range of baby monitor is 50 meter radius.
The baby monitor will therefore cover an entire area of 50 meter radius.
Formula for finding the area of a circle is = π r 2 = π X r X r
Meaning: π = 3.142, r = radius of signal monitor
Therefore Area of circle = Square meters of coverage of baby monitor = 3.142 X 50 meters X 50 meters = 157.14 m2 (157.14 meters squared)
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2 less than a number n is (n - 2 ) and 3 times this is 3(n - 2 ), thus
3(n - 2) ≥ 5n ( greater than or equal to 5 times n )
3n - 6 ≤ 5n ( subtract 3n from both sides )
- 6 ≥ 2n ( divide both sides by 2 )
- 3 ≥ n or n ≤ - 3
Since n is less than or equal to - 3 use bracket ]
n ∈ ( - ∞, - 3 ] ← solution set
Answer:
![EF = 5](https://tex.z-dn.net/?f=%20EF%20%3D%205%20)
![GH = 5](https://tex.z-dn.net/?f=%20GH%20%3D%205%20)
Step-by-step explanation:
Length of EFis the distance between E(-4, -3) and F (-1, 1).
![EF = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}](https://tex.z-dn.net/?f=%20EF%20%3D%20%5Csqrt%7B%28x_2%20-%20x_1%29%5E2%20%2B%20%28y_2%20-%20y_1%29%5E2%7D%20)
Let,
![E(-4, -3) = (x_1, y_1)](https://tex.z-dn.net/?f=%20E%28-4%2C%20-3%29%20%3D%20%28x_1%2C%20y_1%29%20)
![F(-1, 1) = (x_2, y_2)](https://tex.z-dn.net/?f=%20F%28-1%2C%201%29%20%3D%20%28x_2%2C%20y_2%29%20)
![EF = \sqrt{(-1 -(-4))^2 + (1 -(-3))^2}](https://tex.z-dn.net/?f=%20EF%20%3D%20%5Csqrt%7B%28-1%20-%28-4%29%29%5E2%20%2B%20%281%20-%28-3%29%29%5E2%7D%20)
![EF = \sqrt{(3)^2 + (4)^2}](https://tex.z-dn.net/?f=%20EF%20%3D%20%5Csqrt%7B%283%29%5E2%20%2B%20%284%29%5E2%7D%20)
![EF = \sqrt{9 + 16} = \sqrt{25}](https://tex.z-dn.net/?f=%20EF%20%3D%20%5Csqrt%7B9%20%2B%2016%7D%20%3D%20%5Csqrt%7B25%7D%20)
![EF = 5](https://tex.z-dn.net/?f=%20EF%20%3D%205%20)
Distance between G(-2, -3) and H(3, -3)
![GH = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}](https://tex.z-dn.net/?f=%20GH%20%3D%20%5Csqrt%7B%28x_2%20-%20x_1%29%5E2%20%2B%20%28y_2%20-%20y_1%29%5E2%7D%20)
Let,
![G(-2, -3) = (x_1, y_1)](https://tex.z-dn.net/?f=%20G%28-2%2C%20-3%29%20%3D%20%28x_1%2C%20y_1%29%20)
![H(3, -3) = (x_2, y_2)](https://tex.z-dn.net/?f=%20H%283%2C%20-3%29%20%3D%20%28x_2%2C%20y_2%29%20)
![GH = \sqrt{(3 -(-2))^2 + (-3 -(-3))^2}](https://tex.z-dn.net/?f=%20GH%20%3D%20%5Csqrt%7B%283%20-%28-2%29%29%5E2%20%2B%20%28-3%20-%28-3%29%29%5E2%7D%20)
![GH = \sqrt{(5)^2 + (0)^2}](https://tex.z-dn.net/?f=%20GH%20%3D%20%5Csqrt%7B%285%29%5E2%20%2B%20%280%29%5E2%7D%20)
![GH = \sqrt{25 + 0} = \sqrt{25}](https://tex.z-dn.net/?f=%20GH%20%3D%20%5Csqrt%7B25%20%2B%200%7D%20%3D%20%5Csqrt%7B25%7D%20)
![GH = 5](https://tex.z-dn.net/?f=%20GH%20%3D%205%20)
ANSWER
![\cos(y) = \frac{4}{5}](https://tex.z-dn.net/?f=%5Ccos%28y%29%20%20%3D%20%20%5Cfrac%7B4%7D%7B5%7D%20)
EXPLANATION
From the mnemonics SOH-CAH-TOA.
We want to find the cosine of y
CAH means cosine ratio involves adjacent over the hypotenuse.
![\cos(y) = \frac{adjacent}{hypotenuse}](https://tex.z-dn.net/?f=%20%5Ccos%28y%29%20%20%3D%20%20%5Cfrac%7Badjacent%7D%7Bhypotenuse%7D%20)
From the right by triangle, the side ajacent to angle y is 64 units and the hypotenuse is 80 units.
![\cos(y) = \frac{64}{80}](https://tex.z-dn.net/?f=%20%5Ccos%28y%29%20%20%3D%20%20%5Cfrac%7B64%7D%7B80%7D%20)
![\cos(y) = \frac{4}{5}](https://tex.z-dn.net/?f=%5Ccos%28y%29%20%20%3D%20%20%5Cfrac%7B4%7D%7B5%7D%20)
Answer:
answer is
Step-by-step explanation:
The number of students in order from least to greatest is 14<24<27<54
Step-by-step explanation:
Total students = 150
16% students play soccer
No. of students play soccer = 
9/25 play basketball
No. of students play basketball = 
 play football
No. of students play football = 
No. of students do not play anything = 14
The number of students in order from least to greatest is 14<24<27<54