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Alchen [17]
3 years ago
15

Explain how the connotations of the bolded words in each sentence impact the meaning being conveyed.

Chemistry
1 answer:
pav-90 [236]3 years ago
6 0

Answer:

Find the explanation below.

Explanation:

Sentence A: In sentence A, the bolded words create a positive undertone to the entire meaning of the text. Words such as unimaginable accomplishment, stunning, and fascinated produce a pleasing and heartening mood. They make it clearer to the reader that this action by the scientists elicited a favorable response from the viewers.

Sentence B: In sentence B, there is a negative undertone to the text. The use of descriptors such as shocking, recklessly, alarmed, tells the reader of the unfavorable response the action of the scientists produced in the viewers. A gloomy mood is thus created.

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The molar heat of vaporization of hydrogen fluoride (HF) is 31.18 kJ/mol. How much heat is released when 100.0 g HF condenses at
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The acceleration due to gravity on Earth is 9.80 m/s 2 . If the mass of a honeybee is 0.000100 kilograms, what is the weight of
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Okay so i think the answer to this is.

weight=mg

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5 0
4 years ago
Do parts a, b and c
Leona [35]

Answer:- (a)The pH of the buffer solution is 3.90.

(b) the pH of the solution after addition of HCl would be 3.60.

(c) the pH of the buffer solution after addition of NaOH is 4.32.

Solution:- (a) It is a buffer solution so the pH could easily be calculated using Handerson equation:

pH=Pka+log(\frac{base}{acid})

pKa can be calculated from given Ka value as:

pKa=-logKa

pKa=-log(6.3*10^-^5)

pKa = 4.20

let's plug in the values in the Handerson equation:

pH=4.20+log(\frac{0.025}{0.05})

pH = 4.20 - 0.30

pH = 3.90

The pH of the buffer solution is 3.90.

(b) Let's say the acid is represented by HA and the base is represented by A^- .

Original mili moles of HA from part a = 0.05(100) = 5

original mili moles of A^- from part a = 0.025(100) = 2.5

mili moles of HCl that is H^+ added = 0.100(10.0) = 1

This HCl reacts with the base present in the buffer to make HA as:

A^-+H^+\rightarrow HA

Total mili moles of HA after addition of HCl = 5+1 = 6

mili moles of base after addition of HCl = 2.5-1 = 1.5

Let's plug in the values in the Handerson equation again. Here, we could use the mili moles to calculate the pH. The answer remains same even if we use the concentrations also as the final volume is same both for acid and base.

pH=4.20+log(\frac{1.5}{6})

pH = 4.20 - 0.60

pH = 3.60

So, the pH of the solution after addition of HCl would be 3.60.

(c) mili moles of NaOH or OH^- added to the original buffer = 0.05(15.0) = 0.75

This OH^- reacts with HA to form A^- as:

HA+OH^-\rightarrow H_2O+A^-

mili moles of HA after addition of NaOH = 5-0.75 = 4.25

mili moles of A^- after addition of NaOH = 2.5+0.75 = 3.25

Let's plug in the values again in Handerson equation:

pH=4.20+log(\frac{3.25}{4.25})

pH = 4.20 - 0.12

pH = 4.32

So, the pH of the buffer solution after addition of NaOH is 4.32.

7 0
3 years ago
Convert 15.0 grams of H2 to molecules of H2.
faust18 [17]
7.440919102327499 is your answer hope this helps
7 0
3 years ago
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