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Sever21 [200]
2 years ago
10

I NEED HELP ASAP!!!!!!!!!!! WITHIN THE HOUR Thanks

Chemistry
2 answers:
Alex17521 [72]2 years ago
6 0
Its D because

Li = 6
Be =9
C= 12
O=15
velikii [3]2 years ago
5 0

Answer:

C

Explanation:

Actually, arranged to the size of smallest to least atom radius size = C

Atomic sizes generally get smaller as you go from L to R across a row of the periodic table.

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Describe how you would make 6.0 L of a 0.100 M KCl solution from a 4.0 M stock KCl solution.
Galina-37 [17]

Answer:

0.15 l of 4.0 m stock KCl solution should betaken

Explanation:

N1V1=N2V2

6*0.1=V2*4

V2=0.15L

5 0
2 years ago
Two colorless solutions are mixed together bubbles form as the solution is stirred give to possible explanations for this result
Aleks [24]
One possible answer could be that a chemical reaction has occurred.
5 0
3 years ago
the diagram below shows DNA molecules. What do the broken lines connected to hydrogen atoms represent in this diagram?
uranmaximum [27]

Answer is: hydrogen bonds.

Hydrogen bond is an electrostatic attraction between two polar groups that occurs when a hydrogen atom (H), covalently bound to a highly electronegative atom such as flourine (F), oxygen (O) and nitrogen (N) atoms.

According to the principle of base pairing hydrogen bonds could form between adenine and thymine (two hydrogen bonds between this nucleobases) and guanine and cytosine (three hydrogen bonds between this nucleobases).

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5 0
3 years ago
Read 2 more answers
Michelle is trying to find the average atomic mass of a sample of an unknown
GREYUIT [131]

The average atomic mass of her sample is 114.54 amu

Let the 1st isotope be A

Let the 2nd isotope be B

From the question given above, the following data were obtained:

  • Abundance of isotope A (A%) = 59.34%
  • Mass of isotope A = 113.6459 amu
  • Mass of isotope B = 115.8488 amu
  • Abundance of isotope B (B%) = 100 – 59.34 = 40.66%
  • Average atomic mass =?

The average atomic mass of the sample can be obtained as follow:

Average \: atomic \: mass \:  =  \frac{mass \: of \: A \times A\%}{100}  + \frac{mass \: of \: B \times B\%}{100}  \\  \\ Average \: atomic \: mass \:  =  \frac{113.6459\times 59.34}{100} + \frac{115.8488\times 40.66}{100} \\  \\ Average \: atomic \: mass \:  = 114.54 \: amu  \\  \\

Thus, the average atomic mass of the sample is 114.54 amu

Learn more about isotope: brainly.com/question/25868336

3 0
2 years ago
A sample of gas at 1.10 atm has a volume of 326 mL. What is the new volume if the pressure is changed to 1.90 atm?
Brut [27]

Answer

For this we use ideal gas equation which is:

P1V1 = P2V2

P1 = 1.10 atm

V1 = 326 ml

P2 = 1.90

V2 = ?

By rearranging the ideal gas equation:

V2 =  P1V1 ÷ P2

V2 = 1.10 × 326 ÷1.90

V2 = 358.6 ÷ 1.90

V2 = 188.7 ml

8 0
3 years ago
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