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Darya [45]
3 years ago
12

PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ HELP AND SHOW YOUR WORK

Mathematics
2 answers:
Leviafan [203]3 years ago
8 0

Answer:

n<2

Step-by-step explanation:

-2n+5>1

-2n>1-5

(-2n>-4)divide by -2

USPshnik [31]3 years ago
5 0

Answer:

n<2

Step-by-step explanation:

Solve the Inequality for n

Isolate the variable by dividing each side by factors that don't contain the variable.

-2n+5>1

-2n>1-5

(-2n>-4)divide by -2

Interval Notation: (−∞,2)

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A model for the population in a small community after t years is given by P(t)=P0e^kt.
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\bf \textit{Amount of Population Growth}\\\\&#10;A=Ie^{rt}\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;I=\textit{initial amount}\\&#10;r=rate\to r\%\to \frac{r}{100}\\&#10;t=\textit{elapsed time}\\&#10;\end{cases}

a)

so, if the population doubled in 5 years, that means t = 5.  So say, if we use an amount for "i" or P in your case, to be 1, then after 5 years it'd be 2, and thus i = 1 and A = 2, let's find "r" or "k" in your equation.

\bf \textit{Amount of Population Growth}\\\\&#10;A=Ie^{rt}\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\to &2\\&#10;I=\textit{initial amount}\to &1\\&#10;r=rate\\&#10;t=\textit{elapsed time}\to &5\\&#10;\end{cases}&#10;\\\\\\&#10;2=1\cdot e^{5r}\implies 2=e^{5r}\implies ln(2)=ln(e^{5r})\implies ln(2)=5r&#10;\\\\\\&#10;\boxed{\cfrac{ln(2)}{5}=r}\qquad therefore\qquad \boxed{A=e^{\frac{ln(2)}{5}\cdot t}} \\\\\\&#10;\textit{how long to tripling?}\quad &#10;\begin{cases}&#10;A=3\\&#10;I=1&#10;\end{cases}\implies 3=1\cdot e^{\frac{ln(2)}{5}\cdot t}

\bf 3=e^{\frac{ln(2)}{5}\cdot t}\implies ln(3)=ln\left( e^{\frac{ln(2)}{5}\cdot t} \right)\implies ln(3)=\cfrac{ln(2)}{5} t&#10;\\\\\\&#10;\cfrac{5ln(3)}{ln(2)}=t\implies 7.9\approx t

b)

A = 10,000, t = 3

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3 years ago
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I hope this helps.
5 0
2 years ago
The perimeter of a rectangle is 42 inches. If the width of the rectangle is 6 inches, what is the length?
snow_lady [41]

Answer:

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Step-by-step explanation:

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Read 2 more answers
twice the number of donuts was only 6 less than 24 times the number of cream puffs. 10 times the number of cream puffs was only
Karolina [17]

donuts and cream puffs were  45 & 4 respectively !

<u>Step-by-step explanation:</u>

Here we have , twice the number of donuts was only 6 less than 24 times the number of cream puffs. 10 times the number of cream puffs was only 5 less than the number of donuts   We need to find how many donuts and cream puffs were there . Let's find out:

Let number of donuts and cream puffs are x & y respectively ! So ,

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According to this statement equation is :

⇒ 2x=24y-6

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According to this statement equation is :

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Equation (1) & (2) :

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⇒ 2y=8

⇒ y=4

Putting  y=4 in  x=12y-3  :

⇒ x = 12(4)-3

⇒ x = 45

Therefore , donuts and cream puffs were  45 & 4 respectively !

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