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3 years ago

What do -4 (x+7)-4 equal

Mathematics

1 answer:

Dima020 [189]3 years ago

5 0

Answer:

-4x-32 Can i please get a brainliest because this correct.

Step-by-step explanation:

−4(x+7)−4

Distribute:

=(−4)(x)+(−4)(7)+−4

=−4x+−28+−4

Combine Like Terms:

=−4x+−28+−4

=(−4x)+(−28+−4)

=−4x+−32

Answer:

=−4x−32

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Find an exponential function that passes through each pair of points.<br><br>(2,1.75) & (-2,28)

dusya [7]

Answer:

$f(x) = 7\, ((1/2)^{x})$ .

Step-by-step explanation:

An exponential function is typically in the form $f(x) = a\, (b^{x})$ , where $a$ and $b$ ( $b > 0$ ) are constants to be found.

In this question:

$f(2) = 1.75$ means that $a\, (b^{2}) = 1.75$ .

$f(-2) = 28$ means that $a\, (b^{-2}) = 28$ .

Divide one of the two equations by the other to eliminate $a$ and solve for $b$ .

The number of the right-hand side of the second equation is larger than that of the first equation. Hence, divide the second equation with the first:

$\displaystyle \frac{a\, (b^{-2})}{a\, (b^{2})} = \frac{28}{1.75}$ .

$\displaystyle b^{-4} = 16$ .

$b^{-1} = 2$ .

$\displaystyle b = \frac{1}{2}$ .

Substitute $b = (1/2)$ back into either equation (for example, the first equation) and solve for $a$ :

$a\, ((1/2)^{2}) = 1.75$ .

$a = 7$ .

Substitute $a = 7$ and $b = (1/2)$ into the other equation. That equation should also be satisfied.

Therefore, this function would be:

$f = 7\, ((1 / 2)^{x})$ .

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2 years ago

Simplify.<br><br> 6x+4y-4x+5y+5

riadik2000 [5.3K]

Answer:

2x + 9y + 5

Step-by-step explanation:

Combine like terms:

(6x - 4x) + (4y + 5y) + 5

2x + 9y + 5

5 0

3 years ago

What is the range of the relation? {(1, 2), (2, 4), (3, 2), (4, 6)} A.{2, 4} B.{1, 2, 3, 4, 6} C.{2, 4, 6} D.{1, 2, 3, 4}

tamaranim1 [39]

$(1)\ \ \ \ range:\ \ \ \{2, 4, 6\}\ \ \ \Rightarrow\ \ \ Ans.\ C\\\\(2)\ \ \ function:\ \ \ \{(1, 2); (2, 2); (3, 2); (4, 2)\}\ \ \ \Rightarrow\ \ \ Ans.\ D\\\\(3)\ \ \ f(4)=2-3\cdot4=2-12=-10\ \ \ \Rightarrow\ \ \ Ans.\ C\\\\(4)\ \ \ direct:\ \ \ y=ax\ \ \ \Rightarrow\ \ \ y= \frac{1}{3} x\ \ \ \Rightarrow\ \ \ Ans.\ B\\\\(5)\ \ \ f(x)=ax\ \ \ and\ \ \ f(4)=12\\.\ \ \ \ \ \Rightarrow\ \ \ 12=a\cdot4\ \ \ \Rightarrow\ \ \ a=3\ \ \ \Rightarrow\ \ \ f(x)=3x\ \ \ \Rightarrow\ \ \ Ans.\ (?)\\\\$

$(6)\ \ \ f(x)=ax^2\ \ \ and\ \ \ f(2)=48\\.\ \ \ \Rightarrow\ \ 48=a\cdot2^2\ \ \Rightarrow\ \ a=48:4=12\ \ \Rightarrow\ \ f(x)=12x^2\ \Rightarrow\ \ Ans.\ C\\\\(7)\ \ \ inversely:\ \ \ f(x)= \frac{a}{x} \ \ \ and\ \ \ f(2)=4\\.\ \ \ \Rightarrow\ \ \ 4= \frac{a}{2} \ \ \ \Rightarrow\ \ \ a=4\cdot2=8\ \ \ \Rightarrow\ \ \ y= \frac{8}{x}\ \ \ \Rightarrow\ \ \ Ans.\ B$

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3 years ago

The length of human pregnancies from conception to birth varies according to an approximately normal distribution with a mean of

Varvara68 [4.7K]

Answer:

A) 68.33%

B) (234, 298)

Step-by-step explanation:

We have that the mean is 266 days (m) and the standard deviation is 16 days (sd), so we are asked:

A. P (250 x < 282)

P ((x1 - m) / sd < x < (x2 - m) / sd)

P ((250 - 266) / 16 < x < (282 - 266) / 16)

P (- 1 < z < 1)

P (z < 1) - P (-1 < z)

If we look in the normal distribution table we have to:

P (-1 < z) = 0.1587

P (z < 1) = 0.8413

replacing

0.8413 - 0.1587 = 0.6833

The percentage of pregnancies last between 250 and 282 days is 68.33%

B. We apply the experimental formula of 68-95-99.7

For middle 95% it is:

(m - 2 * sd, m + 2 * sd)

Thus,

m - 2 * sd <x <m + 2 * sd

we replace

266 - 2 * 16 <x <266 + 2 * 16

234 <x <298

That is, the interval would be (234, 298)

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2 years ago

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Vanyuwa [196]

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3 years ago