Answer:
λ = 5.656 x 10⁻⁷ m = 565.6 nm
Explanation:
Using the formula of fringe spacing from the Young's Double Slit experiment, which is given as follows:
where,
λ = wavelength = ?
Δx = fringe spacing = 1.6 cm = 0.016 m
L = Distance between slits and screen = 4.95 m
d = slit separation = 0.175 mm = 0.000175 m
Therefore,
<u>λ = 5.656 x 10⁻⁷ m = 565.6 nm</u>
Answer:
The water is 1310.75 meters deep.
Explanation:
The question gives us the speed of sound and the time the sonar signal takes to travel to the bottom of the water and back.
To find out the distance, we should first divide the time in half, so we only consider the time taken for the sound to reach the bottom of the water body.
This means:
Time = 1.75 / 2 = 0.875 seconds
The distance traveled in this time is:
Distance = Speed * Time
Distance = 1498 * 0.875
Distance = 1310.75 meters
Thus, the water is 1310.75 meters deep.
Answer:
Explanation:
Given that the force of the particle is,
Now it can be further written as
Now the initial conditions are v=1 at t=0.
So,
Now the velocity will become.
And,
And, another initial condition is x=0 at t=0
Now,
Answer:
= 625 nm
Explanation:
We now that for
for maximum intensity(bright fringe) d sinθ=nλ n=0,1,2,....
d= distance between the slits, λ= wavelength of incident ray
for small θ, sinθ≈tanθ= y/D where y is the distance on screen and D is the distance b/w screen and slits.
Given
d=1.19 mm, y=4.97 cm, and, n=10, D=9.47 m
applying formula
λ= (d*y)/(D*n)
putting values we get
on solving we get
= 625 nm