exit temperature of air is 776.128k
the mass flow rate of exhaust gases is 14.89kg/s
Explanation: plz brainly me
Answer:
( About ) 6.8nC
Explanation:
We are given the equation |Q2| = mgd^2 / kQ1. Let us substitute known values into this equation, but first list the given,
Charge Q2 = +45nC = (45 × 10⁻⁹) C
mass of charge Q2 = 4.5 μg, force of gravity = 4.5 μg × 9.8 m/s² = ( 4.41 × 10^-5 ) N,
Distance between charges = 25 cm = 0.25 m,
k = Coulomb's constant = 9 × 10^9
_______________________________________________________
And of course, we have to solve for the magnitude of Q2, represented by the charge magnitude of the charge on Q2 -
(4.41 × 10^-5) = [(9.0 × 10⁹) × (45 × 10⁻⁹) × Q₂] / 0.25²
_______________________________________________________
Solution = ( About ) 6.8nC
Answer:
4.28 s
Explanation:
after two seconds (2 s) His friends is
d = 3.5 m/s x 2 s = 7 meter ahead.
in this state, a bicylist start from initial velocity vo = 0 m/s and accelerat 2.4 m/s²
then, when bicylist reach his friend
t friend = t bicyclist = t
d bicylist = d friend + d
-------
d friend = 3.5 . t
d bicylist = vo . t + ½ a t²
d friend + d = vo . t + ½ a t²
3.5 t + 7 = 0 . t + ½ . 2.4 . t²
3.5 t + 7 = 1.2 t²
0 = 1.2 t² - 3.5 t - 7
t = -1.363 and t = 4.28
take the positive one
Small objects vibrate quickly and produce lots of waves each second, and as the length of the bells are short the wave length become short too,so small bells have a high frequency hence high pitch.
Answer:
5 m/s
Explanation:
he accelerates by 5 m/s so he accelerates from 10 m/s to 15 m/s so he accelerates 5 m/s