Answer:
The change in internal energy of the system is -17746.78 J
Explanation:
Given that,
Pressure 
Remove heat 
Radius = 0.272 m
Distance d = 0.163 m
We need to calculate the internal energy
Using thermodynamics first equation
...(I)
Where, dU = internal energy
Q = heat
W = work done
Put the value of W in equation (I)

Where, W = PdV
Put the value in the equation


Hence, The change in internal energy of the system is -17746.78 J
Water as it's the highest specific heat capacity
Hope this helps x
Answer:
v=0.60 m/s
Explanation:
Given that
m ₁= 390 kg ,u ₁= 0.5 m/s
m₂ = 250 kg ,u₂ = 0.76 m/s
As we know that if there is no any external force on the system the total linear momentum of the system will be conserve.
Pi = Pf
m ₁u ₁+m₂u₂ = (m₂ + m ₁ ) v
Now putting the values in the above equation
390 x 0.5 + 250 x 0.76 = (390 + 250 ) v

v=0.60 m/s
Therefore the velocity of the system will be 0.6 m/s.
A. microscopes !!!!!!!!!!
I think the answer is A because it’s a better explanation