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evablogger [386]
3 years ago
13

A bullet was fired from a gun. The bullet had a mass of 50g and the kinetic energy of the bullet was 25 kJ. How fast did it go?

Physics
1 answer:
Elenna [48]3 years ago
5 0

Answer:

given \:  \\ mass \: (m) = 50g \\ kinetic \: enegy \: (k.e) = 25kj \\ velocity(v) = x \\ form \\ k.e =  \frac{1}{2}  \times MV ^{2}  \\ 25 =  \frac{1}{2}  \times 50 \times v {}^{2}  \\ 25 = 25 \times v {}^{2} \\ v {}^{2}  =  \frac{25}{25}  \\ v {}^{2}  = 1 \\ v =  \sqrt{1}  \\ v = 1ms {}^{ - }

the car it go fast with velocity 1m/s

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Answer:

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Given that,

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\Delta K.E=\dfrac{1}{2}m(v_{2}^2-v_{1}^2)

\Delta K.E=\dfrac{1}{2}\times10000\times(172.22^2-0^2)

\Delta K.E=\dfrac{1}{2}\times10000\times(172.22^2)

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The change in kinetic energy will be 150 MJ.

Hence, The change in potential energy and kinetic energy are 980 MJ and 148.3 MJ.

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