Answer:
The circuit is shown in my attachments, please take a good look
Answer:
The correct option is d ( Neither A nor B)
Explanation:
Technician A made 2 mistakes in his statement.Firstly the tire is self supporting not self sealing.
Secondly, this tire does not provide permanent sealing of punctured area option a is incorrect.
This self-supporting tire after being affected with complete air leakage can temporarily bear the load of the car and avoid rolling over a distance of 80 km at a maximum speed of 55 mph. Here is what technician B suggested incorrectly as the tire after being.Here the technician B suggested incorrectly as the tire after being affected with puncture can not travel at any speed so option B is wrong
Since option a and b are incorrect and c is invalid.
Answer:
70,900
Explanation:
Given :
True stress (psi) _____ True strain (psi)
48400 ______________ 0.11
60400 ______________ 0.19
Using ratio simplification :
Let :
s = True stress ; t = true strain
s1 = 48400
s2 = 60400
t1 = 0.11
t2 = 0.19
True stress, s0 ; needed to produce a True plastic strain, tp = 0.26
(s0 - s1) / (s2 - s1) = (tp - t1) / (t2 - t1)
(s0 - 48400)/(60400 - 48400) = (0.26 - 0.11)/(0.19 - 0.11)
(s0 - 48400)/12000 = 0.15/0.08
Cross multiply :
0.08(s0 - 48400) = 0.15 * 12000
0.08s0 - 3872 = 1800
0.08s0 = 1800 + 3872
0.08s0 = 5672
s0 = 5762 / 0.08
s0 = 70,900
The true stress required to produce a true plastic strain of 0.26 is 70,900
Answer:
Exit Temperature= T2=563.6 °R
Exit Pressure= P2= 30.06 lbf/in^2
Mass Flow rate=1.276 lb/sec
Explanation:
Answer is explained in detailed way in the attached files.
Answer:
Plain Sawn. At least 95 percent of all hardwood lumber commercially produced in the U.S. is flat or plain sawn. ...
Quarter Sawn. In this method, the log actually is cut into quarters, then sawn quarter by quarter. ...
Explanation:
