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son4ous [18]
3 years ago
13

For every 3 packages that Marcella wraps she uses 1/2 of a roll of wrapping paper if she uses 2 1/2 rolls of wrapping paper how

many packages has she wrapped
Engineering
2 answers:
Tju [1.3M]3 years ago
7 0

Answer:

The answer is 15 packages

Explanation: 1/2 = 3packages in total she has 2 1/2. So 1/2+ 1/2 = 3 + 3= 6

then again we do 1/2 + 1/2 = 3 + 3 = 6 + 6 = 12 and then since it is 2 1/2 we add 3 again so 12 + 3 = 15 packages

hram777 [196]3 years ago
6 0
She wrapped 5 packages
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Degger [83]

Answer:

I can help but I need to know what it looking for

5 0
2 years ago
An ac source of period T and maximum voltage V is connected to a single unknown ideal element that is either a resistor, and ind
Misha Larkins [42]

Answer:

The unknown element is Capacitor.

Explanation:

The sinusoidal voltage is given as:

v(t) = V Sin (ωt + Ф)

Where:

V = Amplitude of Voltage

ω = 2π / T = > Time period (T)

Ф = phase shift

Considering no horizontal phase shift in the wave form, the equation can be written as:

v(t) = V Sin (ωt)--------(1)

Since, current in the capacitor can be given as:

i(t) = C dv(t)/dt = ωCV Cos (ωt)--------(2)

Now, checking all conditions:

At t=0 :

Equation (1) implies:

v(t) = V Sin [(2π/T)(0)] = V Sin (0)

v(t) = 0

The above finding satisfies the condition in the question. Now checking other conditions.

At t = T/4:

Equation (2) implies:

i(t) = ωCV Cos [(2π/T)(T/4)] = ωCV Cos [(π/2)] = ωCV (0)

i(t) = 0

At t = T/2 :

Equation (2) implies:

i(t) = ωCV Cos [(2π/T)(T/2)] = ωCV Cos [(π)] = ωCV (-1)

i(t) = - ωCV = max amplitude of current in negative direction

All three conditions of voltage and currents of question are satisfied with equations of capacitor hence, the unknown element is capacitor.

4 0
3 years ago
Describe the refrigeration cycle & how it transfers heat, including all the components & lines. be sure to discuss why t
Amanda [17]

Heat can be diverted away from the area you want to cool using the refrigeration cycle, also known as a heat pump cycle. This is done by repeatedly compressing and expanding the working refrigerant (air, water, synthetic refrigerants, etc.) to change its pressure.

<h3>What is the cycle of a heat pump?</h3>
  • In order to heat the air within a building, a heat pump warms the air outside by drawing heat from it and adding it to it. The following procedure is used to achieve this: A gas is created when liquid refrigerant absorbs heat from the ambient air in the "evaporator."
  • The pressure buildup from the compressor raises the temperature of the refrigerant, just like it does with everything that is put under pressure. The refrigerant is a heated vapor, ranging in temperature from 120° to 140°F, when it exits the compressor.
  • The chemical refrigerant, once transformed from a gas to a liquid state, has a remarkable capacity to absorb heat. The heat inside your house might be absorbed and released outside when the refrigerant undergoes a state shift as a result of compression and pressurization.  

To learn more about Compressor refer to:

brainly.com/question/29345949

#SPJ4

6 0
1 year ago
What were some challenges engineers faced in designing aqueducts.
Harman [31]

Answer:

Valleys and low-lying areas, hills and mountains, were some of the challenges faced by Roman engineers who built Aqueducts. The first aqueduct was built in Rome around 312 BC. By the 3rd century AD, it became common.

8 0
2 years ago
A common procedure for measuring the velocity of an air stream involves insertion of an electrically heated wire (called a hot-w
timurjin [86]

Answer:

V = 6.33 m/s

Explanation:

Given:

- The length of the wire L = 0.02 m

- The diameter of the wire D = 0.0005 m

- The calibration expression V = 0.0000625*h^2

- Environment temperature T_inf = 298 K

- Surface temperature T_s = 348 K

- The voltage drop dV = 5 V

- The electric current I = 0.1 A

Find:

- the velocity of Air

Solution:

- Calculate the surface area of the wire:

                             A = pi*D*L

                             A = pi*(0.0005)*(0.02) = 0.00003142 m^2

- The rate of energy in the wire P:

                             P = I*dV = 0.1*5 = 0.5 W

- Apply Newton's Law of Cooling:

                            P = h*A*(T_s - T_inf)

                            h =  P /A*(T_s - T_inf)

Plug in the values:

                             h= 0.5/ 0.00003142*(348 - 298)

                             h = 318.27 W /m^2K

- Using the calibration relationship given, compute the velocity of air:

                             V = 6.25*10^-5 * h^2

                             V = 6.25*10^-5 * (318.27)^2

                             V = 6.33 m/s

5 0
3 years ago
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