Question

A circular specimen of MgO is loaded in three-point bending. Calculate the minimum possible radius of the specimen without fracture, given that: the applied load is 5560 N the flexural strength is 105 MPa the separation between the supports is 45 mm Input your answer as X.XX mm, but without the unit of mm.

Answer 1

Answer:

radius = 9.1 × $10^{-3}$ m

Explanation:

given data

applied load = 5560 N

flexural strength = 105 MPa

separation between the support =  45 mm

solution

we apply here minimum radius formula that is

radius = $\sqrt[3]{\frac{FL}{\sigma \pi}}$      .................1

here F is applied load and  is length

put here value and we get

radius =  $\sqrt[3]{\frac{5560\times 45\times 10^{-3}}{105 \times 10^6 \pi}}$  

solve it we get

radius = 9.1 × $10^{-3}$ m