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snow_lady [41]
3 years ago
15

While discussing run-flat tires: Technician A says that some are self-sealing tires and are designed to quickly and permanently

seal sidewall area punctures. Technician B says that most of these tires have reinforced sidewalls that are able to support the vehicle at any speed without air in the tire. Who is correct?
a. Technician A
b. Technician B
c. Both A and B
d. Neither A nor B
Engineering
1 answer:
musickatia [10]3 years ago
4 0

Answer:

The correct option is d ( Neither A nor B)

Explanation:

Technician A made 2 mistakes in his statement.Firstly the tire is self supporting not self sealing.

Secondly, this tire does not provide permanent sealing of punctured area option a is incorrect.

This self-supporting tire after being affected with complete air leakage can temporarily bear the load of the car and avoid rolling over a distance of 80 km at a maximum speed of 55 mph. Here is what technician B suggested incorrectly as the tire after being.Here the technician B suggested incorrectly as the tire after being affected with puncture can not travel at any speed so option B is wrong

Since option a and b are incorrect and c is invalid.

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Answer: a

Explanation:

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Find an expectation value in the n th state of the harmonic oscillator.Find an expectation value in the n th state of the harmon
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The classical motion for an oscillator that starts from rest at location x₀ is

                                           x(t) = x₀ cos(ωt)

The probability that the particle is at a particular x at a particular time t

is given by ρ(x, t) = δ(x − x(t)), and we can perform the temporal average

to get the spatial density. Our natural time scale for the averaging is a half

cycle, take t = 0 → π/ ω

Thus,

ρ =   \frac{1}{\pi / w} \int\limits^\pi_0 {d(x - x_o cos(wt))} \, dt

Limit is 0 to π/ω

We perform the change of variables to allow access to the δ, let y = x₀ cos(ωt)  so that

ρ(x) = -\frac{w}{\pi } \int\limits^x_x {\frac{d ( x - y)}{x_ow sin(wt)} } \, dy

Limit is x₀ to -x₀

\frac{1}{\pi } \int\limits^x_x {\frac{d (x-y)}{x_o\sqrt{1 - cos^2(wt)} } } \, dy

Limit is -x₀ to x₀

= \frac{1}{\pi } \int\limits^x_x {\frac{d(x-y)}{\sqrt{x_o^2 - y^2} } } \, dy\\ \\= \frac{1}{\pi\sqrt{x_o^2 - x^2}  }

This has \int\limits^x_x {p(x)} \, dx  = 1 as expected. Here the limit is -x₀ to x₀

The expectation value is 0 when the ρ(x) is symmetric, x ρ(x) is asymmetric and the limits of integration are asymmetric.

6 0
4 years ago
Using the AASHTO procedure, determine the thickness required for a base and a surface layer over existing subgrade. The structur
garri49 [273]

Answer:

<u>the thickness required would be 12 inch HMA and granular base layer of 6 inches</u>

Explanation:

structural number = 4.5

stone base course material coefficient = 0.13

hma material layer coefficient = 0.40

drainage coefficient = 0.90

we will use layered analysis procedure to get thickness

D1 >= sN1/a1

when we cross multiply,

sN1 = a1D1 >=sN1

D2 >= -sN2-sN1/a2m2

sN2* + sN1* >= sN2

D3 >= sN3-(sN1*+sN2*)/a2m2

where a1,a2,a3 = layer coefficient

d1 d2 d3 = actual thickness

m2,m3 = coefficient of base

a1 = 0.4

a1 = 0.13

sN = 4.5

m2 = 0.9

D1 >= sN1/a1 = 4.5/0.4

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7 0
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Consider the following chain-reaction mechanism for the high-temperatureformation of nitric oxide, i.e., the Zeldovich mechanism
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Answer: hello attached below is the properly written chain reaction  to your question

answer :

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d[N] / dt = k_{1f} [O] [N_{2}] + K_{2f}  [N][O_{2} ] - K_{3f}[N][OH]

Explanation:

<u>write out expressions for  d[NO] / dt and d[N] / dt</u>

Given :

properly written chain reaction ( attached below)

Expression for d[NO] / dt can be written as

k_{1f} [O] [N_{2}] + K_{2f}  [N][O_{2} ] + K_{3f}[N][OH]

Expression for d[N] / dt can be written as

k_{1f} [O] [N_{2}] + K_{2f}  [N][O_{2} ] - K_{3f}[N][OH]

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