Answer:
Second puck travels farther
Step-by-step explanation:
Maximum height of first puck = 3 feet
The height of a second hockey puck is modeled by:
To find maximum height of second puck
Equate the derivative equals to 0
0.15-0.002x=0
75 = x
At x = 75
So, The maximum height of second puck is greater than first puck
So, Second puck travels farther
I'm not entirely sure what you're looking for, but here are your options. If you need a perfect square, I'd go for the 12 and 12, but I hope this helps?
Answer:
<u>Step-by-step explanation:</u>
y = A cos (Bx - C) + D
D = (max + min)/2 = (3 - 11)/3 = -4
A = max - D = 3 - (-4) = 7
Period = 9π/4 - π/4 = 8π/4 = 2π
B = Period/2π = 2π/2π = 1
Phase Shift = π/4 - 0 = π/4
C = B · Phase Shift = 1 · π/4 = π/4
Equation:
y = 7 cos (1·x - π/4) + (-4)