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joja [24]
4 years ago
11

Lupert lemon started his two watches at the same time. One is slow and loses two minutes every hour; the other one is fast and g

ains one minute every hour. How long will it take for thr faster watch to br one hour ahead of the slower watch
Mathematics
1 answer:
vaieri [72.5K]4 years ago
6 0

Answer: 20 hours

Step-by-step explanation:

Since, One watch is slow and loses two minutes every hour

⇒ 1 hour of slow watch = 62 minutes

And, the other one is fast and gains one minute every hour.

⇒ 1 hour of fast watch = 59 minutes,

Hence, in 1 hour, the difference between slow and fast watch in 1 hour = 62 - 59 = 3 minutes.

⇒ The between slow and fast watch in 20 hours = 20 × 3 = 60 minutes or 1 hour.

Hence, after 20 hours the difference between the watches will be 1 hours.

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