Question

A 2.0 kg cart moving right at 5.0 on a frictionless track collides with a 3.0 kg cart initially at rest. The 2.0 kg

Answer 1

final speed of the 3.0 kg cart is 2.67 m/s .

Step-by-step explanation:

Here we have , A 2.0 kg cart moving right at 5.0 on a friction less track collides with a 3.0 kg cart initially at rest. The 2.0 kg  cart has a final speed of 1.0 to the left. We will use law of conservation of momentum: For a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

$m_1(v_1)+m_2(v_2) =m_1(v_3)+m_2(v_4)$

⇒ $m_1(v_1)+m_2(v_2) =m_1(v_3)+m_2(v_4)$

⇒ $2(5)+3(0) =2(1)+3(v_4)$

⇒ $10 =2+3(v_4)$

⇒ $3(v_4) = 8$

⇒ $(v_4) = \frac{8}{3}$

⇒ $(v_4) = 2.67$

Therefore, final speed of the 3.0 kg cart is 2.67 m/s .