Its y-values increase at a nonconstant rate as its x-value increases
Answer:
volume of the solid generated when region R is revolved about the x-axis is π ₀∫^a (
x + b )² dx
Step-by-step explanation:
Given the data in the question and as illustrated in the image below;
R is in the region first quadrant with vertices; 0(0,0), A(a,0) and B(0,b)
from the image;
the equation of AB will be;
y-b / b-0 = x-0 / 0-a
(y-b)(0-a) = (b-0)(x-0)
0 - ay -0 + ba = bx - 0 - 0 + 0
-ay + ba = bx
ay = -bx + ba
divide through by a
y =
x + ba/a
y =
x + b
so R is bounded by y =
x + b and y =0, 0 ≤ x ≤ a
The volume of the solid revolving R about x axis is;
dv = Area × thickness
= π( Radius)² dx
= π (
x + b )² dx
V = π ₀∫^a (
x + b )² dx
Therefore, volume of the solid generated when region R is revolved about the x-axis is π ₀∫^a (
x + b )² dx
9514 1404 393
Answer:
5√5
Step-by-step explanation:
Use the distance formula:
d = √((x2 -x1)² +(y2 -y1)²)
d = √((-7-(-2))² +(-7-3)²) = √((-5)² +(-10)²) = √(25 +100)
d = √125 = √(25·5)
d = 5√5 . . . . distance between the points
-8x2-x +5 hope this helps
Y=3x+10
10 represents the fee
X= amount of hours
3 is the cost per hour.