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hjlf
3 years ago
5

The compass is a small bar magnet that’s free to spin. Based on what you observed, is the coil of wire with current passing thro

ugh it a magnet?
Physics
2 answers:
Ipatiy [6.2K]3 years ago
4 0

Answer:

Yes, the coil of wire with current passing through it is a magnet.

Explanation:

d1i1m1o1n [39]3 years ago
3 0

Answer:

People have been aware of magnets and magnetism for thousands of years. The earliest records date back to ancient times, particularly in the region of Asia Minor called Magnesia—the name of this region is the source of words like magnet. Magnetic rocks found in Magnesia, which is now part of western Turkey, stimulated interest during ancient times. When humans first discovered magnetic rocks, they likely found that certain parts of these rocks attracted bits of iron or other magnetic rocks more strongly than other parts. These areas are called the poles of a magnet. A magnetic pole is the part of a magnet that exerts the strongest force on other magnets or magnetic material, such as iron. For example, the poles of the bar magnet shown in Figure 20.2 are where the paper clips are concentrated.

A bar magnet with paper clips attached to it.

Figure 20.2 A bar magnet with paper clips attracted to the two poles.

If a bar magnet is suspended so that it rotates freely, one pole of the magnet will always turn toward the north, with the opposite pole facing south. This discovery led to the compass, which is simply a small, elongated magnet mounted so that it can rotate freely. An example of a compass is shown Figure 20.3. The pole of the magnet that orients northward is called the north pole, and the opposite pole of the magnet is called the south pole.

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Two asteroids collide and stick together. The first asteroid has a mass of 15\times 10^3\,\mathrm{kg}15×10 3 kg and is initially
statuscvo [17]

Answer:

Final speed is 900.06 m/s at 0.2215^{\circ}  

Solution:

As per the question:

Mass of the first asteroid, m = 15\times 10^{3}\kg

Mass of the second asteroid, m' = 20\times 10^{3}\kg

Initial velocity of the first asteroid, v = 770 m/s

Initial velocity of the second asteroid, v' = 1020 m/s

Angle between the two initial velocities, \theta = 20^{\circ}

Now,

Since, the velocities and hence momentum are vector quantities, then by the triangle law of vector addition of 2 vectors A and B, the resultant is given by:

\vec{R} = \sqrt{A^{2} + 2ABcos\theta + B^{2}}

Thus applying vector addition and momentum conservation, the final velocity is given by:

(m + m')v_{final} = \sqrt{(mv)^{2} + 2(mv)(m'v')cos20^{\circ} + (m'v')^{2}}                               (1)

Now,

(m +m')v_{final} = (35\times 10^{3})v_{final}

(mv)^{2} = (15\times 10^{3}\times 770)^{2} = 1.334\times 10^{14}

(m'v')^{2} = (20\times 10^{3}\times 1020)^{2} = 4.16\times 10^{14}

2(mv)(m'v')cos20^{\circ} = 2(15\times 10^{3}\times 770)(20\times 10^{3}\times 1020)cos20^{\circ} = 4.43\times 10^{14}

Now, substituting the suitable values in eqn (1), we get:

v_{final} = 900.06\ m/s

Now, the direction for the two vectors is given by:

\theta = sin^{- 1} \frac{m'v'sin20^{\circ}}{(m + m')v_{final}}

\theta = sin^{- 1} \frac{20\times 10^{3}\times 1020sin20^{\circ}}{(35\times 10^{3})\times 900.06} = 0.2215^{\circ}

5 0
3 years ago
What is the weight of a 2.06 kg text book. show work please
salantis [7]

The weight of anything is (mass) x (gravity in the place where the thing is).

             Gravity on Earth is about 9.8 newtons per kilogram, so on Earth,
             the weight of the book is

                          (2.06 kg) x (9.8 N/kg) = <em>20.19 newtons</em> .


Another way to get around it is:  

               On Earth, 1 kg of mass weighs about 2.205 pounds, so on earth,
               the weight of the book is

                         (2.06 kg) x (2.205 pounds/kg) = <em>4.54 pounds </em>.


7 0
4 years ago
An airplane maintains a speed of 627 km/h relative to the air it is flying through as it makes a trip to a city 787 km away to t
amid [387]

Answer:1.33 hr

Explanation:

Given

Speed of airplane relative to air=627 km/h

Distance traveled =787 km

Speed of wind=38.4 km/h

Wind is blowing in opposite direction therefore net speed is

v_{net}=627-38.4=588.6 km/h

thus time taken is

t=\frac{distance}{speed}

t=\frac{787}{588.6}=1.33 hr

4 0
4 years ago
I need help in my physics class and show me how it’s done
Korolek [52]

If we have the angle and magnitude of a vector A we can find its Cartesian components using the following formula

A_x = |A|cos(\alpha)\\\\A_y = |A|sin(\alpha)

Where | A | is the magnitude of the vector and \alpha is the angle that it forms with the x axis in the opposite direction to the hands of the clock.

In this problem we know the value of Ax and Ay and we need the angle \alpha.

Vector A is in the 4th quadrant

So:

A_x = 6\\\\A_y = -6.5

So:

|A| = \sqrt{6^2 + (-6.5)^2}\\\\|A| = 8.846

So:

Ay = -6.5 = 8.846cos(\alpha)\\\\sin(\alpha) = \frac{-6.5}{8.846}\\\\sin(\alpha) = -0.7348\\\\\alpha = sin^{- 1}(- 0.7348)

\alpha = -47.28 ° +360° = 313 °

\alpha = 313 °

Option 4.

4 0
4 years ago
a car with a mass of 1200 kilograms is moving around a circular curve at a uniform velocity of 20 m/s the centripetal force on t
jek_recluse [69]
Coupla things wrong with this question, Sam.
Let's clean those up first, and then we'll work on the answer.

-- The car is NOT moving with uniform velocity.
'Velocity' includes both speed and direction.  If either of these
changes, it's a change of velocity.
On a circular track, the car's direction is CONSTANTLY changing,
so its velocity is too. 
The thing that's uniform is its speed, not its velocity.

-- A 'neutron' is a subatomic particle found in the nucleus of most
atoms.  It's not a unit of force.  The unit of force is the 'Newton'.
_______________________

OK. A centripetal force of 6,000 newtons keeps 1,200 kg of mass
moving in a circle at 20 m/s.

The formula:

                                     Centripetal force = (mass) (speed)² / (radius)

Multiply each side
by 'radius':                (centripetal force) x (radius) = (mass) x (speed)²

Divide each side by
'centripetal force':       Radius = (mass) x (speed)² / (centripetal force)

Write in the numbers
that we know:              Radius = (1200 kg) (20 m/s)² / (6000 Newtons)

                                                 = (1200 kg) (400 m²/s²) / (6000 Newtons)

                                                 = (480,000 kg-m²/s²) / (6000 kg-m/s²)

                                                 = (480,000 / 6000) meters
                                                
                                                 =         80 meters .   
8 0
3 years ago
Read 2 more answers
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