Answer:
2872.8 N
Explanation:
We have the following information
m =n72kg
Δy = 18m
t = 0.95s.
From here we use the equation
Δy=1/2at2 in order to solve for the acceleration.
So a
=( 2x 18m)/(0.95s²)
= 36/0.9025
= 39.9m/s2.
From there we use the equation
F = ma
F=(72kg) x (39.9)
= 2872.8N.
2872.8N is the average net force exerted on him in the barrel of the cannon.
Thank you!
Answer:
1.907 x 10⁻⁵ J.
Explanation:
Given,
Volume of space, V = 5.20 m³
Assuming the intensity of sunlight(S) be equal to 1.1 x 10³ W/m².
Electromagnetic energy = ?


where c is the speed of light.


Hence, Electromagnetic energy is equal to 1.907 x 10⁻⁵ J.
Answer:
<h3>0.445</h3>
Explanation:
In friction, the coefficient of friction formula is expressed as;

Ff is the frictional force = Wsinθ
R is the reaction = Wcosθ
Substitute inti the equation;

Given
θ = 24°

Hence the coefficient of kinetic friction between the box and the ramp is 0.445