These are the characteristics that apply:
- In a solution taste sour: which is consequence of the H+ concentration.
- Corrode metals: the H+ ion reacts with the metal producing a salt and water
-Produce hydronium ion in solution: as per the Bronsted - Lowry definition an acid is a substance that donates a proton, H+. This proton will react with H2O to form H3O+ (hydronium), as per this scheme:
HA + H2O --> A(-) + H3O(+)
<span>Chemical Energy is converted into Mechanical Energy.
</span>When gasoline is burned in a car engine, chemical energy is converted into mechanical energy.
Answer:
5N
Explanation
convert grams to kg and multipy with 10 (.5 *10)=5N
The equation for force is F=ma. Because we have the value of mass (0.42 kg) and the acceleration (14.8 m/s^2), simply plug them into the equation for force to get
![0.42 \times 14.8 = 6.22](https://tex.z-dn.net/?f=0.42%20%5Ctimes%2014.8%20%3D%206.22)
The answer is 6.22 N because newtons are the unit used to measure force.
Answer:
D = -4/7 = - 0.57
C = 17/7 = 2.43
Explanation:
We have the following two equations:
![3C + 4D = 5\ --------------- eqn (1)\\2C + 5D = 2\ --------------- eqn (2)](https://tex.z-dn.net/?f=3C%20%2B%204D%20%3D%205%5C%20---------------%20eqn%20%281%29%5C%5C2C%20%2B%205D%20%3D%202%5C%20---------------%20eqn%20%282%29)
First, we isolate C from equation (2):
![2C + 5D = 2\\2C = 2 - 5D\\C = \frac{2 - 5D}{2}\ -------------- eqn(3)](https://tex.z-dn.net/?f=2C%20%2B%205D%20%3D%202%5C%5C2C%20%3D%202%20-%205D%5C%5CC%20%3D%20%5Cfrac%7B2%20-%205D%7D%7B2%7D%5C%20--------------%20eqn%283%29)
using this value of C from equation (3) in equation (1):
![3(\frac{2-5D}{2}) + 4D = 5\\\\\frac{6-15D}{2} + 4D = 5\\\\\frac{6-15D+8D}{2} = 5\\\\6-7D = (5)(2)\\7D = 6-10\\\\D = -\frac{4}{7}](https://tex.z-dn.net/?f=3%28%5Cfrac%7B2-5D%7D%7B2%7D%29%20%2B%204D%20%3D%205%5C%5C%5C%5C%5Cfrac%7B6-15D%7D%7B2%7D%20%2B%204D%20%3D%205%5C%5C%5C%5C%5Cfrac%7B6-15D%2B8D%7D%7B2%7D%20%3D%205%5C%5C%5C%5C6-7D%20%3D%20%285%29%282%29%5C%5C7D%20%3D%206-10%5C%5C%5C%5CD%20%3D%20-%5Cfrac%7B4%7D%7B7%7D)
<u>D = - 0.57</u>
Put this value in equation (3), we get:
![C = \frac{2-(5)(\frac{-4}{7} )}{2}\\\\C = \frac{\frac{14+20}{7}}{2}\\\\C = \frac{34}{(7)(2)}\\\\C = \frac{17}{7}\\](https://tex.z-dn.net/?f=C%20%3D%20%5Cfrac%7B2-%285%29%28%5Cfrac%7B-4%7D%7B7%7D%20%29%7D%7B2%7D%5C%5C%5C%5CC%20%3D%20%5Cfrac%7B%5Cfrac%7B14%2B20%7D%7B7%7D%7D%7B2%7D%5C%5C%5C%5CC%20%3D%20%5Cfrac%7B34%7D%7B%287%29%282%29%7D%5C%5C%5C%5CC%20%3D%20%20%5Cfrac%7B17%7D%7B7%7D%5C%5C)
<u>C = 2.43</u>