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AnnZ [28]
4 years ago
13

An ice skater weighs 500 [N]. He is coasting to the right at a constant velocity of 2 [m/s]. Assume

Physics
1 answer:
luda_lava [24]4 years ago
4 0

Answer:

The net force on the skater is zero. (F_{net} = 0\,N)

Explanation:

According to Newton's First Law, an object is at equilibrium when either it is at rest or moves at constant velocity, which means a net force of zero. Based on the given statement, there are no external forces acting on skate and, therefore, the net force on the skater is zero. (F_{net} = 0\,N)

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4. How long does it take a car traveling at 45 km/h to travel 100.0 m?<br> 4500m
Trava [24]

Answer:

8.0s

Explanation:

45 km/h ÷ 3.6  = 12.5 m/s

t.v = d/t

vt/v = d/v

t = d/v = 100.0m /12.5 m/s = 8.0s

Hope this helps!!

8 0
3 years ago
A large heavy rock, a medium size stone and a small marble are dropped at the same time from the roof of a building. Neglecting
KengaRu [80]
They would all strike the ground at the same time. If air resistance is neglected for example in an airless tube, then gravity is the only force acting on them and it has the same effect on them dropping so the drop at the same speed.
6 0
3 years ago
Read 2 more answers
a radio controlled car rolls 10 m south then reverses direction and rolls 8 m north the car traveled a distance of 18 m and has
EastWind [94]

The displacement is 2 m south

Explanation:

Distance and displacement are two different quantities:

  • Distance is the total length of the path covered by an object during its motion, regardless of the direction. It is a scalar quantity
  • Displacement is a vector connecting the initial position to the final position of motion of an object. The magnitude of the displacement is the distance in a straight line between the two points

For the car in this problem, the motion is:

10 m south

8 m north

Taking north as positive direction, we can describe the two parts of the motion as

d_1 = -10 m

d_2 = +8 m

Therefore,  the final position of the car with respect to the original position is

x_f = -10 + 8 = -2 m

which means 2 m south: so, the displacement of the car is 2 m south.

Learn more about  distance and displacement:

brainly.com/question/3969582

#LearnwithBrainly

5 0
3 years ago
Lightning heats the surrounding air to ___. A. 30000C B. 300C C. 300000C D. 3000C
Blizzard [7]
A bolt of lightning<span>, which can reach temperatures of roughly 30,000 kelvins (53,540 degrees Fahrenheit). The sun, on the other hand, is eclipsed in this case, its surface temperature is just 6,000 kelvins (10,340 degrees Fahrenheit)
</span><span>So,it can be around 30,000 degrees.The answer is Choice A.</span>
3 0
3 years ago
Read 2 more answers
Imagine you are in an open field where two loudspeakers are set up and connected to the same amplifier so that they emit sound w
weeeeeb [17]

Question:

If you are 3.00 m from speaker A directly to your right and 3.50 m from speaker B directly to your left. What is the shortest distance d you need to walk forward to be at a point where you cannot hear the speakers?

Answer:

The shortest distance d you need to walk forward to be at a point where you cannot hear the speakers is 5.625 m

Explanation:

Shortest distance is given by

For constructive interference of wave, we have

\Delta r_{construct} = 2nλ/2

For destructive interference of wave, we have

\Delta r_{destruct} = (2n+1)λ/2

That is the difference in the number of wavelength between constructive and destructive interference is λ/2

We note that our positioning is 3.0 m from the first speaker and 3.5 m from the second, Which is of the form 2n and 2n + 1

Therefore when we walk forward away from the two speakers, we cannot hear the speakers at

Δr = λ/2 = r_B - r_A

Which is the distance between the points where we have constructive and destructive interference or where there is destructive interference between the waves

Where:

r_A =  Distance from  speaker A and

r_B = Distance from  speaker B

λ/2 = (344 m/s /688 Hz)/2

= 1/4

For

λ/2 = r_B - r_A  we have

√(3.5² +d²) - √(3²+d²) = 1/4

∴ d = 5.625 m

6 0
3 years ago
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