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Eddi Din [679]
3 years ago
6

As a rocket ascends, its acceleration increases even though the net force on it stays constant. why? (assume a traveling distanc

e small enough that the thrust, acceleration due to gravity and atmosphere do not change. the faster a rocket moves the more acceleration is imparted to it from a given force. as a rocket ascends it's momentum increases with it's speed. the greater the momentum of the rocket, the greater the acceleration imparted to it from a given force. as the rocket ascends, fuel is burned at a faster rate resulting in a larger acceleration. the rocket's mass decreases as its fuel is consumed. the same net force acting on a smaller mass results in a larger acceleration.
Physics
2 answers:
topjm [15]3 years ago
5 0
<span>the rocket's mass decreases as its fuel is consumed. the same net force acting on a smaller mass results in a larger acceleration</span>
bogdanovich [222]3 years ago
5 0

Answer:

Explanation:

A rocket is provided thrust and acceleration through the fuel which is filled within it, burning of fuel at faster rate provide larger acceleration to the rocket. However, as the fuel get consumed the mass of rocket also decreases and with the reduction of it's mass it's momentum and speed increases thereby, it ascends with larger acceleration despite the force of gravity acting upon it in opposite direction.

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The Earth orbits around the sun because the gravitational force that the sun
kotykmax [81]
<h3>Question -:</h3>

The Earth orbits around the sun because the gravitational force that the sun

exerts on the Earth:

O A. causes Earth's acceleration toward the sun.

O B. is very small because the sun is so far from the Earth.

O c. is smaller than the force the Earth exerts on the sun.

O D. pushes the Earth away from the sun.

<h3>Answer -:</h3>

O A. causes Earth's acceleration toward the sun.

<em>I </em><em>hope </em><em>this</em><em> </em><em>helps</em><em>,</em><em> </em><em>have </em><em>a </em><em>nice </em><em>time </em><em>ahead!</em>

5 0
2 years ago
A mass weighting 16 lbs stretches a spring 3 inches. The mass is in a medium that exerts a viscous resistance of 20 lbs when the
const2013 [10]

Answer:

The equation for the object's displacement is u(t)=0.583cos11.35t

Explanation:

Given:

m = 16 lb

δ = 3 in

The stiffness is:

k=\frac{m}{\delta } =\frac{16}{3} =5.33lb/in

The angular speed is:

w=\sqrt{\frac{k}{m} } =\sqrt{\frac{5.33*386.4}{16} } =11.35rad/s

The damping force is:

F_{D} =cu

Where

FD = 20 lb

u = 4 ft/s = 48 in/s

Replacing:

c=\frac{F_{D} }{u} =\frac{20}{48} =0.42lbs/in

The critical damping is equal:

c_{c} =\frac{2k}{w} =\frac{2*5.33}{11.35} =0.94lbs/in

Like cc>c the system is undamped

The equilibrium expression is:

u(t)=u(o)coswt+u'(o)sinwt\\u(o)=7=0.583\\u'(o)=0\\u(t)=0.583coswt\\u(t)=0.583cos11.35t

3 0
3 years ago
there is a fish called an archer fish that shoots drops of water at insects resting on branches above the water. If the Archer f
Mariulka [41]

Answer:

=3.5 m/s

Explanation:

y = x tanθ - 1/2 g x² / (u²cos²θ )

y = 0.25 , x = 0.5, θ = 40°

.25 = .50 tan40 - .5 x 9.8x x²/ u²cos²40

.25 = .42 - 2.0875/u²

u = 3.5 m / s.

4 0
3 years ago
If there is a huge boulder on your lawn and you want to determine its density, but it is
Olin [163]

There are different options here but all of them work by approximating and assuming.

i) that the boulder is above ground.

ii) that the bottom surface of the boulder is known.

iii) the shape of the boulder is taken into account.

The most accurate way is measuring it by displacement method but the boulder is immovable hence the volume can be calculated by measuring the boulder or a waterproof box to be built around the boulder and calculate the volume occupied by boulder.

All the above methods are estimating methods.

*Another way to find the density is through specific gravity.

S.G = <u>Density</u><u> </u><u>of</u><u> </u><u>object</u>

Density of water

If the material that makes the boulder is known that is if it's stone or a mineral then the specific gravity can be found.

If the boulder is purely rock then S.G lies between 3 - 3.5 and the density of water is known thus the density of the boulder can be found without moving the boulder.

This is what I think after correction and allthe best!

3 0
2 years ago
Read 2 more answers
PLEASE HELP DUE IN MINS. Thanks
rjkz [21]

Answer:

"C" I think....

Explanation:

I am really sorry if I am wrong, but if right, I hope this helps!

4 0
3 years ago
Read 2 more answers
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