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Eddi Din [679]
3 years ago
6

As a rocket ascends, its acceleration increases even though the net force on it stays constant. why? (assume a traveling distanc

e small enough that the thrust, acceleration due to gravity and atmosphere do not change. the faster a rocket moves the more acceleration is imparted to it from a given force. as a rocket ascends it's momentum increases with it's speed. the greater the momentum of the rocket, the greater the acceleration imparted to it from a given force. as the rocket ascends, fuel is burned at a faster rate resulting in a larger acceleration. the rocket's mass decreases as its fuel is consumed. the same net force acting on a smaller mass results in a larger acceleration.
Physics
2 answers:
topjm [15]3 years ago
5 0
<span>the rocket's mass decreases as its fuel is consumed. the same net force acting on a smaller mass results in a larger acceleration</span>
bogdanovich [222]3 years ago
5 0

Answer:

Explanation:

A rocket is provided thrust and acceleration through the fuel which is filled within it, burning of fuel at faster rate provide larger acceleration to the rocket. However, as the fuel get consumed the mass of rocket also decreases and with the reduction of it's mass it's momentum and speed increases thereby, it ascends with larger acceleration despite the force of gravity acting upon it in opposite direction.

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How much mass would pizza dough have after you flatten it
mars1129 [50]

Answer:

the answer is that the dough has the same mass before and after it was flattened

3 0
2 years ago
Read 2 more answers
Two facing surfaces of two large parallel conducting plates separated by 8.5 cm have uniform surface charge densities such that
elena-s [515]

Answer:

positive plate

E = 5.764 KV / m

W = 490eV or 7.85 * 10^-17 J

E_p = 4.74 *10^(-12) eV

E_k = 490 eV

Explanation:

part a

The potential difference between two plates = 490 V

Distance between two plates = 8.5 cm

Answer: The positive plate is at higher potential because of convention.

part b

Electric Field between the plates

E = V / d

E = 490 / 0.085 = 5.764 KV / m

Answer: Electric Field between the plates E = 5.764 KV / m

part c

Work done by electric field

W = V*q

W = 490 * 1.602*10^-19

W = 7.85 * 10^-17 J

or W = 490 eV

Answer: Work done by electric field W = 490eV or 7.85 * 10^-17 J

part d

Potential Energy of an electron gained:

E_p = m_e * g * d / (1.602*10^-19)

E_p =  9.109*10^-31* 9.81 * 0.085 / (1.602*10^-19)

E_p = 4.74 *10^(-12) eV

Very very small E_p approximately 0

Answer: Potential Energy of an electron gained E_p = 4.74 *10^(-12) eV or 0.

part e

Kinetic Energy of an electron gained:

W - E_p = E_k

E_k = 490eV - 4.74*10^(-12)eV

E_k = 490 eV

Answer: Kinetic Energy of an electron gained E_k = 490 eV

7 0
4 years ago
Four charges are on the four corners of a square. Q1 = +5μC, Q2 = -10μC, Q3 = +5μC, Q4 = -10μC. The side length of the square is
Marat540 [252]

Answer:

Explanation:

Electric field due to a point charge Q at a point at distance d is given by the relation

E = \frac{K\times Q}{d^2}

Since Q1 and Q2 are of the same magnitude and distance , so they will create eletric field of same magnitude. Similarly field due to rest of the charges will also be same.

The charges are situated on the corners of a square in such a way that

equal charges of Q1 and Q3 are situated on the diametrically  opposite corners of the square. Fields due to these two charges will be equal and opposite in direction. Therefore net field due to these two  charges will be zero.  

On the same ground, we can say that field due to Q2 and Q4 at the centre will be equal and opposite and therefore they will cancel out each other. Net field at the centre will be zero

Overall, net field due to all the four charges will be zero

3 0
4 years ago
The siren on an ambulance emits a sound of frequency 2.80×103Hz. If the ambulance is traveling at 26.0 m/s (93.6 km/h or 58.2 mi
Norma-Jean [14]

To solve this problem it is necessary to apply the concepts related to the described wavelength through frequency and speed. Mathematically it can be expressed as:

\lambda = \frac{v}{f}

Where,

\lambda = Wavelength

f = Frequency

v = Velocity

Our values are given as,

f = 2.8*10^3Hz

v = 340m/s \rightarrow Speed of sound

Keep in mind that we do not use the travel speed of the ambulance because we are in front of it. In case it approached or moved away we should use the concepts related to the Doppler effect:

Replacing we have,

\lambda = \frac{340}{2.8*10^3}

\lambda = 0.1214m

Therefore the frequency that you hear if you are standing in from of the ambulance is 0.1214m

5 0
3 years ago
What is the energy in space left over from the big bang called
Lilit [14]
It is called the CMBR, which stands for cosmic microwave background radiation. It was discovered by Arno Penzias and Robert Wilson in 1964.
5 0
3 years ago
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