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Eddi Din [679]
3 years ago
6

As a rocket ascends, its acceleration increases even though the net force on it stays constant. why? (assume a traveling distanc

e small enough that the thrust, acceleration due to gravity and atmosphere do not change. the faster a rocket moves the more acceleration is imparted to it from a given force. as a rocket ascends it's momentum increases with it's speed. the greater the momentum of the rocket, the greater the acceleration imparted to it from a given force. as the rocket ascends, fuel is burned at a faster rate resulting in a larger acceleration. the rocket's mass decreases as its fuel is consumed. the same net force acting on a smaller mass results in a larger acceleration.
Physics
2 answers:
topjm [15]3 years ago
5 0
<span>the rocket's mass decreases as its fuel is consumed. the same net force acting on a smaller mass results in a larger acceleration</span>
bogdanovich [222]3 years ago
5 0

Answer:

Explanation:

A rocket is provided thrust and acceleration through the fuel which is filled within it, burning of fuel at faster rate provide larger acceleration to the rocket. However, as the fuel get consumed the mass of rocket also decreases and with the reduction of it's mass it's momentum and speed increases thereby, it ascends with larger acceleration despite the force of gravity acting upon it in opposite direction.

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If a sinusoidal electromagnetic wave with intensity 18 W/m2 has an electric field of amplitude E, then a 36 W/m2 wave of the sam
Neporo4naja [7]

Answer:

The  correct option is D

Explanation:

From the question we are told that

  The intensity of the first  electromagnetic wave is  I =  18 \  W/m^2

  The amplitude of the electric field is  E_{max}_1 =A

   The intensity of the second electromagnetic wave is  I =  36 \  W/m^2

Generally the an electromagnetic wave intensity is mathematically represented as

       I  =  \frac{1}{2} *  \epsilon_o  * c  * E_{max}^2

Looking at this equation we see that

     I \ \ \alpha  \ \ E^2_{max}

=>  \frac{I_1}{I_2}  =  [ \frac{ E_{max}_1}{ E_{max}_2} ] ^2

=>   E_{max}_2 = \sqrt{\frac{x}{y} }  *  E_{max}_1

=>  E_{max}_2 = \sqrt{\frac{36}{18} }  * E        

=>  E_{max}_2 = \sqrt{2 }  E        

5 0
3 years ago
What is the repulsive force between two pith balls that are 10.0 cm apart and have equal charges of -40.0 NC?
galina1969 [7]

Answer:

So the repulsive force between the pith ball will be 1.44\times 10^{-3}N

Explanation:

We have given that the pith ball have the equal charge q = -40 nC =-40\times 10^{-9}C

Distance between the charges = 10 cm =0.1 m

According to coulombs law F=\frac{KQ_1Q_2}{R*2}

F=\frac{9\times 10^9\times -40\times 10^{-9}\times -40\times 10^{-9}}{0.1^2}=1440000\times 10^{-9}=1.44\times 10^{-3}N

So the repulsive force between the pith ball will be 1.44\times 10^{-3}N

5 0
3 years ago
Electrons in an x-ray tube are accelerated through 144 kV and directed toward a target to produce x-rays. Calculate the power of
Katarina [22]

Answer:

Power of the electron beam in the x-ray tube is 2304 W

Explanation:

Given;

voltage of the electron beam in the x-ray tube, V =  144 kV = 144 x 10³ V

current of the electron beam in the x-ray tube, I = 16.0 mA = 16 x 10⁻³ A

Power is given as the product of voltage and current in a circuit.

Power of the electron beam in the x-ray tube, P = V x I

Power of the electron beam in the x-ray tube, P = 144 x 10³ V x 16 x 10⁻³ A

P = 2304 W

Therefore, power of the electron beam in the x-ray tube is 2304 W

7 0
3 years ago
3) Find the missing parts of the triangle (angle and/or sides).<br>​
oee [108]

Answer:

44.4°

Explanation:

Use SOH-CAH-TOA.

Sine = Opposite / Hypotenuse

Cosine = Adjacent / Hypotenuse

Tangent = Opposite / Adjacent

You're given an unknown angle, the adjacent side to that angle, and the hypotenuse.  So use cosine.

Cosine = Adjacent / Hypotenuse

cos A = 10 / 14

A = cos⁻¹(5/7)

A ≈ 44.4°

8 0
3 years ago
How many poles do you expect to see in your magnet? Look around your room. Make a list of 5 items that might be attracted to the
jeyben [28]

Answer:

1.1 Two poles: North and South Poles.

1.2 - Staple pin - Nail - Tip of my phone charger - Metal keys - Cloth Hanger

1.3 - Wooden bed cot - Plastic pen - Game pad - Wooden shelf - Paper - A T-shirt

1.4 Yes

1.5 No

5 0
3 years ago
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