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3 years ago

Auroras occur in the _______. a. troposphere b. stratosphere c. mesosphere d. thermosphere

Physics

2 answers:

Minchanka [31]3 years ago

8 0

Answer;

-Thermosphere

Explanation;

-The thermosphere lies between the exosphere and the mesosphere.It is a region of increasing temperature in Earth’s atmosphere that is located above the mesosphere.

-The thermosphere greatly helps in protecting the earth and making space exploration and modern forms of communication possible. It also supports and protects life on the planet. It recycles water, absorbs the sun's energy, and creates a moderate temperature.

-The aurora (Northern Lights and Southern Lights) mostly occur in the thermosphere. It is a natural electrical phenomenon characterized by the appearance of streamers of reddish or greenish light in the sky, especially near the northern or southern magnetic pole. The effect is caused by the interaction of charged particles from the sun with atoms in the upper atmosphere.

const2013 [10]3 years ago

5 0

the answer is thermosphere

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A careful photographic survey of Jupiter's moon Io by the spacecraft Voyager 1 showed active volcanoes spewing liquid sulfur to

Over [174]

The concept used to solve this problem is that given in the kinematic equations of motion. From theory we know that the change in velocities of a body is equivalent to twice the distance traveled by acceleration, in other words:

$v_f^2-v_i^2 = 2ax$

Where,

$v_{f,i} =$ Final and initial velocity

a = Acceleration

x = Displacement

For the given case, the displacement is equivalent to the height (x = h) and the acceleration is the same gravitational acceleration (a = g). In turn we do not have initial speed therefore

$v_f^2 = 2hg$

$v_f = \sqrt{2hg}$

Our values are given as

$h = 70km = 70*10^3m$

$g = 2m/s^2$

Replacing we have that,

$v_f = \sqrt{2hg}$

$v_f = \sqrt{2(70*10^3)(2)}$

$v_f = 529.15m/s$

Therefore the speed with which the liquid sulfur left the volcano is 529.15m/s

6 0

3 years ago

A copper coin resting on a piece of cardboard is placed on a beaker as shown in the diagram below. When the cardboard is rapidly

Gelneren [198K]

The answer should be d) inertia

6 0

2 years ago

The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 2.0 rev/s in 10.0 s. At th

Arte-miy333 [17]

Answer:

22 revolutions

Explanation:

2 rev/s = 2*(2π rad/rev) = 12.57 rad/s

The angular acceleration when it starting

$\alpha_a = \frac{\Delta \omega}{\Delta t} = \frac{12.57}{10} = 1.257 rad/s^2$

The angular acceleration when it stopping:

$\alpha_o = \frac{\Delta \omega}{\Delta t} = \frac{-12.57}{12} = -1.05 rad/s^2$

The angular distance it covers when starting from rest:

$\omega^2 - 0^2 = 2\alpha_a\theta_a$

$\theta_a = \frac{\omega^2}{2\alpha_a} = \frac{12.57^2}{2*1.257} = 62.8 rad$

The angular distance it covers when coming to complete stop:

$0 - \omega^2 = 2\alpha_o\theta_o$

$\theta_o = \frac{-\omega^2}{2\alpha_o} = \frac{-12.57^2}{2*(-1.05)} = 75.4 rad$

So the total angular distance it covers within 22 s is 62.8 + 75.4 = 138.23 rad or 138.23 / (2π) = 22 revolutions

6 0

3 years ago

Are light waves longitudinal or transverse

Marysya12 [62]

Answer:

Transverse

Explanation:

There are two types of waves, according to the direction of their oscillation:

- Transverse waves: in a transverse wave, the direction of the oscillation is perpendicular to the direction of motion of the wave. Examples of transverse waves are electromagnetic waves

- Longitudinal waves: in a longitudinal wave, the direction of the oscillation is parallel to the direction of motion of the wave. Examples of longitudinal waves are sound waves.

Light waves corresponds to the visible part of the electromagnetic spectrum, which includes all the different types of electromagnetic waves (which consist of oscillations of electric and magnetic fields that are perpendicular to the direction of propagation of the wave): therefore, they are transverse waves.

6 0

3 years ago

Water is discharged from a pipeline at a velocity v (in ft/sec) given by v = 1306p(1/2), where p is the pressure (in psi). If th

shepuryov [24]

Answer:

$a=38.5 ft/sec^{2}$