Rewrite this formula to convert Fahrenheit to Celsius. F= 9/5C + 35

Mathematics

1 answer:

iVinArrow [24]3 years ago

7 0

Answer:

$\huge \purple { \boxed{ C = \frac{5}{9} ( F - 32)}}$

Step-by-step explanation:

I the given problem, there should be 32 in place of 35.

$F = \frac{9}{5} C + 32 \\ F - 32= \frac{9}{5} C \\ 5( F - 32)= 9 C \\ \frac{5}{9} ( F - 32)=C \\ \\ \huge \red{ \boxed{ C = \frac{5}{9} ( F - 32)}}$

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nekit [7.7K]

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Step-by-step explanation:

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2 years ago

Using a stopwatch, Tyrone determines it takes him 58. 2 minutes to travel 30 miles to work. The stopwatch measures to hundredths

nekit [7.7K]

The most accurate determination for the number of 45.36 feet per second Tyrone traveled on his way to work.

Given that,

Using a stopwatch Tyrone determines it takes him 58.2 minutes to travel 30 miles to work the stopwatch measures to hundredths of a minute going by the accuracy of the stopwatch.

We have to determine,

Which is the most accurate determination for the number of feet per second Tyrone traveled on his way to work?

According to the question,

Tyrone determines it takes him 58.2 minutes to travel 30 miles to work,

the stopwatch measures to hundredths of a minute going by the accuracy of the stopwatch are determined by,

$\rm Speed = \dfrac{Distance}{Time}$

Substitute the values in the equation,

$\rm Speed = \dfrac{Distance}{Time}\\\\Speed = \dfrac{30}{58.2}\\\\Speed = \dfrac{50}{97} \ miles \ per \ minute$

If 1 mile = 5,280 feet, then his speed is,

$\rm Speed = \dfrac{50}{97} \ miles \ per \ minute\\\\ Speed = \dfrac{50}{97} \times 5280 \\\\ Speed= \dfrac{26,400}{97}\ feet \ per \ minute\\$

And 1 minute = 60 seconds, then his speed is,

$\rm Speed= \dfrac{26,400}{97}\ feet \ per \ minute\\\\ Speed= \dfrac{26,400}{97} \times \dfrac{1}{60} \\\\ Speed = \dfrac{4400}{97} \ feet \ per \ second \\\\ Speed = 45.36 \ feet \ per \ second$