Rewrite this formula to convert Fahrenheit to Celsius. F= 9/5C + 35

kari74 [83]

54/1,000

just do Length x Width x Height

7 0

3 years ago

A force of $20$ newtons will stretch a spring $5$ centimeters. What is the total number of centimeters that a force of $60$ newt

Aleksandr-060686 [28]

Answer:

Step-by-step explanation:

Hooke's Law applies here, which is a linear relationship. It would be easier to solve this using proportions with N of force on the top and the amount of stretch in cm on the bottom. Set up with our unknown, the number of cm:

$\frac{N}{cm}:\frac{20}{5}=\frac{60}{x}$ and cross multiply:

20x = 300 so

x = 15 cm

6 0

3 years ago

What is the least common multiple for 8 and 13

lara31 [8.8K]

The Lcm is 104. The lcm of 13 and 8 is the smallest positive integer that divides the numbers 13 and 8 without a remainder. Spelled out, it is the least common multiple of 13 and 8. Here you can find the lcm of 13 and 8, along with a total of three methods for computing it. In addition, we have a calculator you should check out. Not only can it determine the lcm of 13 and 8, but also that of three or more integers including thirteen and eight for example. Keep reading to learn everything about the lcm (13,8) and the terms related to it.

7 0

3 years ago

You are competing in a race. The table shows the times from last year's race. You want your time to be last year's median time w

olasank [31]

Answer:

28 ≤ x ≤40

Step-by-step explanation:

Arrange the data from the smallest to the largest

26, 27, 28,32, 32, 33, 35, 36, 38, 40,42,48

Identify the median value

26, 27, 28,32, 32,<u> 33, 35</u>, 36, 38, 40,42,48

Getting the median

(33+35)/2 = 68/2 = 34 minutes

You want your time to be last year's median time with an absolute deviation of at most 6 minutes

This mean ±6 minutes, hence this will be 34 ± 6

34+6=40 and 34-6=28

The inequality will be 28 ≤ x ≤40

7 0

3 years ago

Read 2 more answers

company with a large fleet of cars hopes to keep gasoline costs down and sets a goal of attaining a fleet average of at least 26

podryga [215]

Answer:

$t=\frac{25.02-26}{\frac{4.83}{\sqrt{50}}}=-1.435$

$p_v =P(t_{(49)}$

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its significant lower than 26 so then the specification is satisfied.

Step-by-step explanation:

Data given and notation

$\bar X=25.02$ represent the sample mean

$s=4.83$ represent the sample standard deviation

$n=50$ sample size

$\mu_o =26$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is at least 26 mpg, the system of hypothesis would be:

Null hypothesis: $\mu \geq 26$

Alternative hypothesis: $\mu < 26$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{25.02-26}{\frac{4.83}{\sqrt{50}}}=-1.435$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=50-1=49$

Since is a one sided test the p value would be:

$p_v =P(t_{(49)}$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its significant lower than 26 so then the specification is satisfied.

3 0

3 years ago