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grigory [225]
3 years ago
5

Triangle ABC is a scaled copy of triangle DEF. Side AB measures 12 cm and is the longest side of ABC. Side DE measures 8 cm and

is the longest side of DEF.
a)Triangle ABC is a scaled copy of triangle DEF with what scale factor?

b)Triangle DEF is a scaled copy of triangle ABC with what scale factor?
Mathematics
1 answer:
evablogger [386]3 years ago
4 0

Answer:

a) 3/2 or 1.5

b) 2/3 or ≈.66

Step-by-step explanation:

AB corresponds to DE because they are both the longest sides of their respective triangles.

a) The scale factor would be what you would multiply 8 by to get 12. 12/8 is 3/2 or 1.5

b) The scale factor would be what you multiply 12 by to get 8. 8/12 is 2/3 or ≈.66

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which functions have a range of all real numbers ? check all that apply. A. y=csc x B. y=sec x C. y=tan x D. y= cot x
Natalka [10]

None of these. All of these functions are defined as ratio of trigonometric functions.

Trigonometric functions have infinite zeroes, so when you put them in the denominator, they lead to infinitely many points of ill-definition.

Specifically, we have:

\csc(x) = \dfrac{1}{\sin(x)}

which is undefined at

\sin(x)=0\iff x=k\pi, k\in\mathbb{Z}

\sec(x) = \dfrac{1}{\cos(x)}

which is undefined at

\cos(x)=0\iff x=\dfrac{\pi}{2}+k\pi, k\in\mathbb{Z}

\tan(x) = \dfrac{\sin(x)}{\cos(x)}

which is undefined at

\cos(x)=0\iff x=\dfrac{\pi}{2}+k\pi, k\in\mathbb{Z}

\cot(x) = \dfrac{\cos(x)}{\sin(x)}

which is undefined at

\sin(x)=0\iff x=k\pi, k\in\mathbb{Z}

4 0
3 years ago
Four resistors are connected in series such that their total resistance is 50ohm . If the resistance of resistors is 5 ohm , 10o
Katyanochek1 [597]
<h2>Answer:</h2>

\boxed{R_{4}=20\Omega}

<h2>Step-by-step explanation:</h2>

If resistors are in series, so the current  I is the same in all of them. In this problem we have four resistors. So, we can get a relationship between the Equivalent resistance  of series combination and the four resistors as follows:

R_{eq}=R_{1}+R_{2}+R_{3}+R_{4}

R_{eq} is the total resistance 50\Omega. Moreover:

R_{1}=5\Omega \\ R_{2}=10\Omega \\ R_{3}=15\Omega

Therefore:

50=5+10+15+R_{4} \\ \\ R_{4}=50-(5+10+15) \\ \\ R_{4}=50-30 \\ \\ \boxed{R_{4}=20\Omega}

7 0
3 years ago
Please help with number 1
bezimeni [28]

Answer:

19.0681

Step-by-step explanation:

Given in the question that,

angle from ted to the dog = 60° with the ground

height of ted from the ground =  16ft

To find,

distance between dog and the door of ted's building

Considering the scenario make a right angle triangle:

<h3>By using pythagorus theorem:</h3>

Tan 40 = opposite / adjacent

Tan 40 = height / distance between dog and the door

Tan 40 = 16ft / x

x = 16 / tan40

x = 19.068057

x ≈ 19.0681 (nearest to thousand)

So, the dog need to walk 19.0681ft to reach the open door directly below Ted.

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3 years ago
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Step-by-step explanation:

answer is attached as image

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3 years ago
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Answer:

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Step-by-step explanation:

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