Question

Rodney bought a 25-pound bag of dog food. His dog ate 10 2/5 pounds of the food in the first month and 10 4/5 pounds in the second month. How much dog food, in pounds, was remaining in the bag at the end of the two months?

Answer 1

Answer:

$3\frac{4}{5}$ pounds of food

Step-by-step explanation:

We have been given that Rodney bought a 25-pound bag of dog food. His dog ate $10\frac{2}{5}$ pounds of the food in the first month and $10\frac{4}{5}$ pounds in the second month.  

Let us find the amount of dog-food eaten by dog in two months.

$\text{Dog-food eaten in 2 months}=10\frac{2}{5}+10\frac{4}{5}$

$\text{Dog-food eaten in 2 months}=\frac{52}{5}+\frac{54}{5}$

$\text{Dog-food eaten in 2 months}=\frac{52+54}{5}$

$\text{Dog-food eaten in 2 months}=\frac{106}{5}$

Now we will subtract amount of food eaten by dog from the amount of food initially to find the remaining amount of dog food.

$\text{Remaining amount of dog-food}=25-\frac{106}{5}$

$\text{Remaining amount of dog-food}=\frac{5*25}{5}-\frac{106}{5}$

$\text{Remaining amount of dog-food}=\frac{125}{5}-\frac{106}{5}$

$\text{Remaining amount of dog food}=\frac{125-106}{5}$

$\text{Remaining amount of dog food}=\frac{19}{5}$

$\text{Remaining amount of dog food}=3\frac{4}{5}$

Therefore, $3\frac{4}{5}$ pounds of food was remaining in the bag at the end of the two months.

Answer 2

3 4/5 pounds left.
10 2/5 + 10 4/5 = 21 1/5.
25 - 21 1/5 = 3 4/5.