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SVEN [57.7K]
3 years ago
7

2) For which value of P and W is P + W a rational number? P = 1/(sqrt(3)) And W = 1/(sqrt(6)) 2) P = 1/(sqrt(4)) and w = 1/(sqrt

(9)) 3) P = 1/(sqrt(6)) and w = 1/(sqrt(10)) 4) P = 1/(sqrt(25)) and W = 1/(sqrt(2))
Mathematics
1 answer:
fenix001 [56]3 years ago
4 0

Answer:

  P = 1/(sqrt(4)) and w = 1/(sqrt(9))

Step-by-step explanation:

Only the roots of perfect squares are rational numbers. 2, 3, 6, and 10 are not perfect squares, so their roots are irrational. Both 4 and 9 are perfect squares, so their roots are rational. The sum of rational numbers is a rational number.

  \dfrac{1}{\sqrt{4}}+\dfrac{1}{\sqrt{9}}=\dfrac{1}{2}+\dfrac{1}{3}=\dfrac{5}{6}\quad\text{a rational number}

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kondaur [170]
<span>difference of squares formula:
</span>a^2<span> – b^</span>2<span> = (a + b)(a – b)

</span>so answers are

<span>(3 + xz)(–3 + xz)
</span><span>(y2 – xy)(y2 + xy)
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</span><span>

cause
</span><span>(3 + xz)(–3 + xz)
= </span><span>(xz + 3 )(xz - 3)
= x^2z^2 - 9

--------------
</span>(y^2 – xy)(y^2 + xy)
= y^4 -x^2y^2

----------

<span>(64y^2 + x^2)(–x2 + 64y^2)
=</span>(64y^2 + x2)(64 - x^2)<span>
= 64^2 y^4 - x^4</span>
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3 years ago
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Leno4ka [110]

Answer:

A.

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