3 years ago

What is 67 divided by 9

Mathematics

1 answer:

Wittaler [7]3 years ago

8 0

Answer:

67 ÷ 9 = 7.444

You might be interested in

Find the value of x. 7 D 3 B В х С X =

bekas [8.4K]

Answer:

x = $\sqrt{30}$

Step-by-step explanation:

Using the Altitude- on- Hypotenuse theorem

(leg of Δ ABC )² = (part of hypotenuse below it ) × ( whole hypotenuse )

x² = 3 × (3 + 7) = 3 × 10 = 30 ( take the square root of both sides )

x = $\sqrt{30}$

7 0

3 years ago

5/1/10x - 6/4/5 = 3/1/4

emmasim [6.3K]

I think the answer is A

8 0

4 years ago

Read 2 more answers

Which is bigger 12.5% or 3/20

GaryK [48]

3/20 is 15% so that's bigger

4 0

3 years ago

Read 2 more answers

What 3 digits are in the units period 4,083,817

Dmitry_Shevchenko [17]

So the answers 3,000 cause it said period i mean unit period

6 0

3 years ago

Read 2 more answers

Law of radicals

andrey2020 [161]

Answer:

1) $\sqrt{x^7}=x^{\frac{7}{2}$

2) $\sqrt[3]{y^5}=y^{\frac{5}{3}$

3) $\sqrt[5]{a^{12}}=a^{\frac{12}{5} }$

4) $\sqrt[4]{z^{9}}=z^\frac{9}{4}$

Step-by-step explanation:

1) $\sqrt{x^7}$

We know that $\sqrt{x}=x^{\frac{1}{2}$

So, $\sqrt{x^7}=x^{\frac{7}{2}$

2) $\sqrt[3]{y^5}$

We know that $\sqrt[3]{x}=x^{\frac{1}{3}$

So, $\sqrt[3]{y^5}=y^{\frac{5}{3}$

3) $\sqrt[5]{a^{12}}$

We know that $\sqrt[5]{x}=x^{\frac{1}{5}$

So, $\sqrt[5]{a^{12}}=a^{\frac{12}{5} }$

4) $\sqrt[4]{z^{9}}$

We know that $\sqrt[4]{x}=x^{\frac{1}{4}$

So, $\sqrt[4]{z^{9}}=z^\frac{9}{4}$

6 0

3 years ago