PLEASE HELP WILL MARK BRAINLIEST download pdf to see question

The point c(-3,-2)is translated 1 unit left and 2 units up.what are the coordinates of the resulting point,c

yarga [219]

translation makes this coordinate -4,0

7 0

3 years ago

Solve for x. x/2= -5 x=5/2 x=-5/2 x=-10

NNADVOKAT [17]

X/2 × 2 = -5 × 2

x = -10

6 0

3 years ago

Carrie will spin a spinner 4 times.

natali 33 [55]

Hi!!!! I think the answer is B or D! Have a nice day!!

5 0

3 years ago

Read 2 more answers

Based on a poll, among adults who regret getting tattoos, 12% say that they were too young when they got their tattoos. Assum

Tema [17]

Answer:

a. 0.6588

b. 0.3978

c. 0. 279

Step-by-step explanation:

In the given question the success and failure are given the number of outcomes is fixed so binomial distribution can be applied.

Here success= p = 12 % or 12/100 = 0.12

failure = q= 1-p = 1-0.12 = 0.88

n= 10

Using binomial probability distribution

a. Probability that the number of selected adults saying they were too young is 0 or 1 is calculated as:

P (x=0,1) = 0.12 ⁰(0.88)¹⁰10 C0 + 0.12 (0.88)⁹ 10 C1= 1* 0.279 * 1 + 0.12 ( 0.3165) 10 = 0. 279 + 0.3978= 0.6588

b. Probability that exactly one of the selected adults says that he or she was too young to get tattoos is calculated as

P (x=1) = 0.12 (0.88)⁹ 10 C1= 0.12 ( 0.3165) 10 = 0.3978

c. Probability that none of the selected adults say that they were too young to get tattoos is

P (x=0) = 0.12 ⁰(0.88)¹⁰10 C0 = 1* 0.279 * 1 = 0. 279

4 0

3 years ago

An honest die is rolled. If the roll comes out even (2, 4, or 6), you will win $1; if the roll comes out odd (1,3, or 5), you wi

jenyasd209 [6]

Answer:

(a) 50%

(b) 47.5%

(c) 2.5%

Step-by-step explanation:

According to the honest coin principle, if the random variable X denotes the number of heads in n tosses of an honest coin (n ≥ 30), then X has an approximately normal distribution with mean, $\mu=\frac{n}{2}$ and standard deviation, $\sigma=\frac{\sqrt{n}}{2}$ .

Here the number of tosses is, n = 2500.

Since n is too large, i.e. n = 2500 > 30, the random variable X follows a normal distribution.

The mean and standard deviation are:

$\mu=\frac{n}{2}=\frac{2500}{2}=1250\\\\\sigma=\frac{\sqrt{n}}{2}=\frac{\sqrt{2500}}{2}=25$

(a)

To not lose any money the even rolls has to be 1250 or more.

Since, μ = 1250 it implies that the 50th percentile is also 1250.

Thus, the probability that by the end of the evening you will not have lost any money is 50%.

(b)

If the number of "even rolls" is 1250, it implies that the percentile of 1250 is 50th.

Then for number of "even rolls" as 1300,

1300 = 1250 + 2 × 25

= μ + 2σ

Then P (μ + 2σ) for a normally distributed data is 0.975.

⇒ 1300 is at the 97.5th percentile.

Then the area between 1250 and 1300 is:

Area = 97.5% - 50%

= 47.5%

Thus, the probability that the number of "even rolls" will fall between 1250 and 1300 is 47.5%.

(c)

To win $100 or more the number of even rolls has to at least 1300.

From part (b) we now 1300 is the 97.5th percentile.

Then the probability that you will win $100 or more is:

P (Win $100 or more) = 100% - 97.5%

= 2.5%.

Thus, the probability that you will win $100 or more is 2.5%.

7 0

3 years ago

PLEASE HELP WILL MARK BRAINLIESTdownload pdf to see question