Answer: 
Step-by-step explanation:
To solve for x, you need to get x alone. In this problem, k is a constant.


<span><span>5<span><span>(<span>14−2</span>)^</span>2/</span></span>2
</span><span>=<span><span>5<span>(<span>12^2</span>)/</span></span>2</span></span><span>=
<span><span><span>(5)</span><span>(144)/</span></span>2
</span></span><span>=<span>720/2</span></span><span>=
<span>360</span></span>
Answer:
For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:
Null hypothesis (H0): 
Alternative hypothesis (H1): 
And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 200 or no
Step-by-step explanation:
For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:
Null hypothesis (H0): 
Alternative hypothesis (H1): 
And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 2000 or no
The least common multiple, or LCM, is another number that's useful in solving many math problems. Let's find the LCM of 30 and 45. One way to find the least common multiple of two numbers is to first list the prime factors of each number.
30 = 2 × 3 × 5
45 = 3 × 3 × 5
Then multiply each factor the greatest number of times it occurs in either number. If the same factor occurs more than once in both numbers, you multiply the factor the greatest number of times it occurs.
2: one occurrence
3: two occurrences
5: one occurrence
2 × 3 × 3 × 5 = 90 <— LCM
After you've calculated a least common multiple, always check to be sure your answer can be divided evenly by both numbers.
Answer:
12x+30
Step-by-step explanation:
6(2x+5)
=(6)(2x+5)
=(6)(2x)+(6)(5)
=12x+30