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masha68 [24]
3 years ago
15

Plz help bbbbbbbbbbbbb

Mathematics
1 answer:
lilavasa [31]3 years ago
3 0

Answer:

y = -2x + 1

Step-by-step explanation:

y = mx + b (m is the slope and b is the y-intercept)

y = mx + 1

Equation for slope: \frac{y1-y2}{x1-x2}

(0,1) (1,-1)

\frac{1+1}{0-1} = \frac{2}{-1} = -2

y = -2x + 1

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Solve kx + 10 = 7 for x.​
Vlad1618 [11]

Answer: x=\frac{-3}{k}

Step-by-step explanation:

To solve for x, you need to get x alone. In this problem, k is a constant.

kx=-3

x=\frac{-3}{k}

6 0
3 years ago
What is the simplified form of expression ? 5(14 - 2) to the 2nd power over 2
ser-zykov [4K]
<span><span>5<span><span>(<span>14−2</span>)^</span>2/</span></span>2
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4 0
3 years ago
Read 2 more answers
Suppose I claim that the average monthly income of all students at college is at least $2000. Express H0 and H1 using mathematic
pishuonlain [190]

Answer:

For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:

Null hypothesis (H0): \mu \geq 2000

Alternative hypothesis (H1): \mu

And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 200 or no

Step-by-step explanation:

For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:

Null hypothesis (H0): \mu \geq 2000

Alternative hypothesis (H1): \mu

And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 2000 or no

7 0
3 years ago
Can someone help me on the LCM numbers plzzz
BabaBlast [244]

The least common multiple, or LCM, is another number that's useful in solving many math problems. Let's find the LCM of 30 and 45. One way to find the least common multiple of two numbers is to first list the prime factors of each number.

30 = 2 × 3 × 5
45 = 3 × 3 × 5

Then multiply each factor the greatest number of times it occurs in either number. If the same factor occurs more than once in both numbers, you multiply the factor the greatest number of times it occurs.

2: one occurrence
3: two occurrences
5: one occurrence
2 × 3 × 3 × 5 = 90 <— LCM

After you've calculated a least common multiple, always check to be sure your answer can be divided evenly by both numbers.

4 0
4 years ago
Write a equivalent expression to 6(2x +5)
Nonamiya [84]

Answer:

12x+30

Step-by-step explanation:

6(2x+5)

=(6)(2x+5)

=(6)(2x)+(6)(5)

=12x+30

7 0
3 years ago
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