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2 years ago

Find the volume of a pyramid with a square base, where the side length of the

Mathematics

1 answer:

xeze [42]2 years ago

4 0

Answer: V= 330.513 cm 3

Step-by-step explanation:

Area = l x w and with a square the length and width are the same, additionally the volume of a pyramid can be found by using the formula (L)(w)(h)/3 so

8.7 x 8.7 = 75.69cm^2

75.69 x 13.1 = 991.539

991.539 ÷ 3 = 330.513 cm^3

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Determine whether the vectors u and v are parallel, orthogonal, or neither. u = <6, -2>, v = <8, 24>

Leno4ka [110]

Because 6 * 8 + ( - 2 )* 24 = 48 - 48 = 0 , the vectora u and v are orthogonal ;
Two vectors are orthogonal if their dot product is zero.

5 0

3 years ago

What’s the answer to this problem???

Snowcat [4.5K]

Rewrite the equation into slope intercept form:
8y = -5x+16

divide everything by 8 to get just y
y = -5/8x+2

the slope = -5/8

8 0

3 years ago

Please help me. I need help ASAP.

lara [203]

Answer:

a) 72

b) $259.2

Step-by-step explanation:

A- The bus travels 40 miles on 8 gallons of gasoline. The bus is traveling 360 miles in total.

360/40= 9

9*8= 72

B- $3.60 per gallon and 72 gallons in total.

3.60*72=259.2

$259.2

5 0

3 years ago

Help with 21 would be much appreciated.

umka2103 [35]

Answer:

$\large\boxed{x=2\sqrt{21}\ and\ y=4\sqrt3}$

Step-by-step explanation:

Look at the picture.

ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

$\dfrac{AD}{CD}=\dfrac{CD}{DB}$

We have

$AD=14-8=6\\CD=y\\DB=8$

Substitute:

$\dfrac{6}{y}=\dfrac{y}{8}$ cross multiply

$y^2=(6)(8)$

$y^2=48\to y=\sqrt{48}\\\\y=\sqrt{16\cdot3}\\\\y=\sqrt{16}\ cdot\sqrt3\\\\\boxed{y=4\sqrt3}$

For x use the Pythagorean theorem:

$x^2=6^2+(4\sqrt3)^2\\\\x^2=36+48\\\\x^2=84\to x=\sqrt{84}\\\\x=\sqrt{4\cdot21}\\\\x=\sqrt4\cdot\sqrt{21}\\\\\boxed{x=2\sqrt{21}}$

3 0

3 years ago

DUE NOW

I am Lyosha [343]

The answer of question no.1 and 2 is 1.

Well,the question of 1 and 2 are same.

Look at the attached picture

The answer of question no 3 is 7.

Hope it helps...

Good luck on your assignment

5 0

3 years ago