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Dmitriy789 [7]
3 years ago
10

Two one-coulomb point charges are at a distance of 1.67 m from each other. What is the size of the electric force between the tw

o charges?
The mass of the Falcon Heavy rocket is 1421 t. (The letter t stands for metric ton. One metric ton is equal to one thousand kilograms: 1 t = 1,000 kg.) The force between the two point charges above is equal to the weight of how many Falcon Heavy rockets?
Physics
1 answer:
pychu [463]3 years ago
5 0

Explanation:

The given data is as follows.

       distance (r) = 1.67 m

     q_{1} = q_{2} = 1 C

It is known that formula for electric force between two charges is as follows.

          F = \frac{kq_{1} \times q_{2}}{r^{2}}

Hence, putting the given values into the above formula as follows.

       \frac{9 \times 10^{9} \times 1 \times 1}{(1.67)^{2}}

            = 3.227 \times 10^{9}

As it is given that mass of  Falcon Heavy rocket is 1421. Therefore, weight of 1 Falcon rocket is as follows.

       weight of 1 falcon rocket = 142 \times 10^{3} \times 9.8

Therefore, number of falcon rockets will be calculated as follows.

         No. of falcon rockets = \frac{3.227 \times 10^{9}}{142000 \times 9.8}

                              = 2.31897 \times 10^{3}

                              = 2318.9 falcons

Thus, we can conclude that force between the two point charges above is equal to the weight of 2318.9 Falcon Heavy rockets.

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At t1 = 2.00 s, the acceleration of a particle in counterclockwise circular motion is 6.00 i + 4.00 j m/s2 . It moves at constan
Jet001 [13]

The particle moves with constant speed in a circular path, so its acceleration vector always points toward the circle's center.

At time t_1, the acceleration vector has direction \theta_1 such that

\tan\theta_1=\dfrac{4.00}{6.00}\implies\theta_1=33.7^\circ

which indicates the particle is situated at a point on the lower left half of the circle, while at time t_2 the acceleration has direction \theta_2 such that

\tan\theta_2=\dfrac{-6.00}{4.00}\implies\theta_2=-56.3^\circ

which indicates the particle lies on the upper left half of the circle.

Notice that \theta_1-\theta_2=90^\circ. That is, the measure of the major arc between the particle's positions at t_1 and t_2 is 270 degrees, which means that t_2-t_1 is the time it takes for the particle to traverse 3/4 of the circular path, or 3/4 its period.

Recall that

\|\vec a_{\rm rad}\|=\dfrac{4\pi^2R}{T^2}

where R is the radius of the circle and T is the period. We have

t_2-t_1=(5.00-2.00)\,\mathrm s=3.00\,\mathrm s\implies T=\dfrac{3.00\,\rm s}{\frac34}=4.00\,\mathrm s

and the magnitude of the particle's acceleration toward the center of the circle is

\|\vec a_{\rm rad}\|=\sqrt{\left(6.00\dfrac{\rm m}{\mathrm s^2}\right)^2+\left(4.00\dfrac{\rm m}{\mathrm s^2}\right)^2}=7.21\dfrac{\rm m}{\mathrm s^2}

So we find that the path has a radius R of

7.21\dfrac{\rm m}{\mathrm s^2}=\dfrac{4\pi^2R}{(4.00\,\mathrm s)^2}\implies\boxed{R=2.92\,\mathrm m}

8 0
3 years ago
explain why for thousands of years people believed that stars moved across Earth's sky. Explain why we now have a different expl
Anarel [89]

Answer:

Ptolemy proposed a model, he reference system is centered on the Earth

Copernicus, proposed a deferent system,  this system is centered on the Sun, where it is at the origin of the system

Explanation:

Thousands of years ago, Ptolemy proposed a model to explain the movement of the planets and stars in the sky, in this model the reference system is centered on the Earth, so each body is orbiting in different spheres around the Earth as its center, this system had very complicated calculations and curves to be able to explain the orbits of the planets.

More recently Copernicus, proposed a deferent system, this system is centered on the Sun, where it is at the origin of the system, in this system the movement of the planets are ellipses, which is a much simpler explanation and has been widely accepted, in current systems the reference system is fixed in the bodies more massive, since this simplifies the explanation of the movements.

6 0
3 years ago
Compare and contrast how sound waves behave when they
Kryger [21]

Answer:

They sound tinkling in solid hard like metal.

They can vibrate soft surface

I could just Ans this

3 0
3 years ago
If I push on the wall with 75 Newtons of force, the wall will push back with ______
Sauron [17]

Answer:

(F)reaction = - 75 N

where, negative sign shows opposite direction.

Explanation:

This question can be answered using Newton's third law of motion. The Newton's Third Law of Motion states that for every action force there is an equal but opposite reaction force.

(F)action = - (F)reaction

Hence, in our scenario if we consider the 75 Newton force applied on the wall to be the action force then the reaction force of the wall must be equal to it in opposite direction. Therefore, the reaction push of the wall must be equal to 75 N.

<u>(F)reaction = - 75 N</u>

<u>where, negative sign shows opposite direction.</u>

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3 years ago
How do scientist figure out how diseases start
mel-nik [20]

Answer: sometimes when people start having an outbreak of it, i guess

Explanation:

5 0
3 years ago
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