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erma4kov [3.2K]
3 years ago
13

How do scientist figure out how diseases start

Physics
1 answer:
mel-nik [20]3 years ago
5 0

Answer: sometimes when people start having an outbreak of it, i guess

Explanation:

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jeka94
I think it’s D
I hope this hopes
4 0
4 years ago
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If a nichrome wire has a resistance of 15Ω and is connected across the terminals of a 3.0 V flashlight battery, how much current
scoray [572]

Answer:

0.20 A

Explanation:

The current in the wire is given by Ohm's law:

I=\frac{V}{R}

where

I is the current

V is the voltage

R is the resistance

In this problem,

V = 3.0 V is the voltage

R=15 \Omega is the resistance

Substituting into the formula,

I=\frac{3.0 V}{15 \Omega}=0.20 A

5 0
3 years ago
Suppose a star the size of our Sun, but with mass 9.0 times as great, were rotating at a speed of 1.0 revolution every 7.0 days.
kvasek [131]

Answer:

Its rotation will be 3.89x10⁴ rad/s.

Explanation:

We can find the rotation speed by conservation of the angular momentum:

L_{i} = L_{f}

I_{i}\omega_{i} = I_{f}\omega_{f}   (1)

The initial angular speed is:

\omega_{i} = \frac{1 rev}{7 d} = 0.14 \frac{rev}{d}

The moment of inertia (I) of a sphere is:

I = \frac{2}{5}mr^{2}    (2)

Where m is 9 times the sun's mass and r is the sun's radius

By entering equation (2) into (1) we have:

\frac{2}{5}m_{i}r_{i}^{2}\omega_{i} = \frac{2}{5}m_{f}r_{f}^{2}\omega_{f}

9m_{sun}(696342 km)^{2}0.14\frac{rev}{d} = \frac{3}{4}9m_{sun}(13 km)^{2}\omega_{f}

\omega_{f} = \frac{4}{3}*0.14 \frac{rev}{d}(\frac{696342 km}{13 km})^{2} = 5.36 \cdot 10^{8} \frac{rev}{d}*\frac{1 d}{24 h}*\frac{1 h}{3600 s}*\frac{2\pi rad}{1 rev} = 3.89 \cdot 10^{4} rad/s          

Hence, its rotation will be 3.89x10⁴ rad/s.

I hope it helps you!                                                        

3 0
4 years ago
In this problem you will consider the balance of thermal energy radiated and absorbed by a person.Assume that the person is wear
Alekssandra [29.7K]

Answer:

The thermal power emitted by the body is P_t  = 286.8 \ Wm^{-2}

The net power radiated is  P_{net} = 460 \ W

Explanation:

From the question we are told that

   The length of the assumed humT_{room} = 20 ^oCan body is  L =  2.0 m

   The circumference of the assumed human body is  C  =  0.8 \ m

   The  Stefan-Boltzmann constant is  \sigma  =  5.67 * 10^{-8 } \ W\cdot  m^{-2} \cdot  K^{-4}.

    The temperature of skin T_{body} = 30^oC

     The temperature of the room is  

    The emissivity is  e=0.6

The thermal power radiated by the body is mathematically represented as

           P_t  =  e *  \sigma * T_{body}^4

substituting value

        P_t  =  0.6 * 5.67*10^{-8} *  (303)^4

        P_t  = 286.8 \ Wm^{-2}

The net power radiated by the body is mathematically evaluated as

    P_{net}  =  P_t *  A

Where A is the surface area of the body which is mathematically evaluated as

     A =  C* L

substituting values

      A =  0.8 * 2

      A =  1.6 m^2

=>    P_{net} =  286.8 * 1.6

=>   P_{net} =  460 \ W

8 0
4 years ago
Which would likely demagnetize a magnetized iron nail?
olga2289 [7]
The answer to this question is dropping it on a hard surface.
8 0
4 years ago
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