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3 years ago

Comporueba si las siguientes fracciones son equivalentes.

Mathematics

1 answer:

NikAS [45]3 years ago

4 0

Answer:

No sé si este es un problema de opción múltiple, pero tanto (A) como (B) son fracciones equivalentes.

Step-by-step explanation:

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A bookstore marks up the price of a book by 25% of the cost from the publisher. Therefore, the

lesya692 [45]

Answer:

(A)

P(60) = 78.98
When the bookstore spends $60 on a textbook, the student pays $78.98

Step-by-step explanation:

Given:

P(x) = 1.053(x+0.25x)

P(60) = 1.053(60+0.25*60)

=1.053(60+15)

=1.053(75)

P(60)=$78.98

Since x is the cost from the publisher, when the bookstore spends $60 on a textbook, the student pays $78.98.

<u>The correct option is A.</u>

3 0

3 years ago

Which is true of point K at (0, –5)? A. Point K is to the left of the y-axis. B. Point K is on the x-axis. C. Point K is on the

nirvana33 [79]

C is the correct one

hope this helps :)

3 0

2 years ago

Can someone plz correct me plz

S_A_V [24]

The answer is D. You’d need to minus the area of the circle away from the area of the triangle to get the area of the shaded region

5 0

2 years ago

Read 2 more answers

Suppose you choose a team of two people from a group of n > 1 people, and your opponent does the same (your choices are allow

jonny [76]

Answer:

The number of possible choices of my team and the opponents team is

$\left\begin{array}{ccc}n-1\\E\\n=1\end{array}\right i^{3}$

Step-by-step explanation:

selecting the first team from n people we have $\left(\begin{array}{ccc}n\\1\\\end{array}\right) = n$ possibility and choosing second team from the rest of n-1 people we have $\left(\begin{array}{ccc}n-1\\1\\\end{array}\right) = n-1$

As { A, B} = {B , A}

Therefore, the total possibility is $\frac{n(n-1)}{2}$

Since our choices are allowed to overlap, the second team is $\frac{n(n-1)}{2}$

Possibility of choosing both teams will be

$\frac{n(n-1)}{2} * \frac{n(n-1)}{2} \\\\= [\frac{n(n-1)}{2}] ^{2}$

We now have the formula

1³ + 2³ + ........... + n³ = $[\frac{n(n+1)}{2}] ^{2}$

1³ + 2³ + ............ + (n-1)³ = $[x^{2} \frac{n(n-1)}{2}] ^{2}$

= $\left[\begin{array}{ccc}n-1\\E\\i=1\end{array}\right] = [\frac{n(n-1)}{2}]^{3}$

4 0

3 years ago

Sara is a drummer in her school is marching band she wants to make a geometrically similar model of a snare drum for her stuffed

strojnjashka [21]

Answer:

Option B.

Step-by-step explanation:

Let the radius of the snare drum = r

and radius of the model = R

Ratio of the dimensions of the snare drum and the model = 1 : 4

So, $\frac{r}{R}=\frac{1}{4}$

Now as per question, dimensions of the snare drum is multiplied by a scale factor of $\frac{1}{2}$

Radius of the snare drum = $\frac{r}{2}$

Ratio of the radius of the snare drum and cylindrical model ,

$\frac{\frac{r}{2}}{R} =\frac{1}{4}$

$\frac{r}{2R}=\frac{1}{4}$

$\frac{r}{R}=\frac{1}{2}$

Therefore, the cylinder with Sara's dimensions will be geometrically similar but the scale factor will be 1 : 2

Option B is the answer.

6 0

2 years ago