8/9
O=16H
H+H+O=water
18H =water molecules
so u can see ratio 16H/!8H=8/9
Answer:
7.8 × 10-5 meters
Step-by-step explanation:
the length of the a human hair= 8.4 x 10^-5
length of the vicuna hair:0.000006 = 0.6 x 10^-5
===========================================
difference between human hair and vicuna hair:
8.4 x 10^-5 - 0.6 x 10^-5 = 10^-5 ( 8.4 - 0.6)
= 10^-5 (7.8)
= 7.8 x 10 ^-5 meters
Answer:
For this case we have this function given:

In order to find the domain we need to find the possible values of x that the function can assume.
And we know that for this case the logarithm for 0 or neagtive numbers is not possible to calculate it, so then we can say that the domain for this case is:

And we can write this in formal notation as:
![D = [ X \in R | X>0]](https://tex.z-dn.net/?f=%20D%20%3D%20%5B%20X%20%5Cin%20R%20%7C%20X%3E0%5D)
And the best answer for this case would be:
all real numbers greater than 0
Step-by-step explanation:
For this case we have this function given:

In order to find the domain we need to find the possible values of x that the function can assume.
And we know that for this case the logarithm for 0 or neagtive numbers is not possible to calculate it, so then we can say that the domain for this case is:

And we can write this in formal notation as:
![D = [ X \in R | X>0]](https://tex.z-dn.net/?f=%20D%20%3D%20%5B%20X%20%5Cin%20R%20%7C%20X%3E0%5D)
And the best answer for this case would be:
all real numbers greater than 0
Answer:
The circumference of the CD is approximately 38 cm
Step-by-step explanation:
The circumference of the CD can be seen as the distance around the CD.
The word "circumference" is used to describe the perimeter of circular objects.
To find an approximate value of the circumference of the CD, we will use this formula.
Circumference = π × diameter
let us take π to be = 3.142
∴ circumference = 3.142 × 12 = 37.6991 cm
we can round this up to teh nearest tenth as 38cm
Answer: Yes it is possible
Here's an example
Original set = {1,2,3,5,7,11}
Subset A = {1,2,3}
Subset B = {3,5,7}
The number 3 is in both subsets A and B.
{1,2,3} is a subset of {1,2,3,5,7,11} since 1,2, and 3 are part of the original set. Similar reasoning applies to subset B as well.
Something like {1,2,9} is not a subset because 9 is not found in the original set.