The phenotype of antenna in crawfish depends on the protein amount in the antenna length. The offspring have different phenotype than their parent because of the amount of protein translated from each parent gene is determining in this.
The gene determines the amount of protein to be present in the antenna to determine its length.
Explanation:
Data given:
Two crawfish parent = medium length antennae, genotyoe Ll
One offspring = short antenna, genotype ll
one offspring = long antennae, genotype LL
The traits in offspring is shown as:
L l
L LL Ll
l Ll ll
The proportion of allele present in the gene determined the length of the antenna in crawfish.
The difference in length of the antenna in crawfish is due to the amount of protein for the phenotype present in the individual. The amount of protein to be expressed in the crawfish is given by both the parents. The tendency of protein expresed define the phenotype of antenna length.
Answer:
the answer is A. E. coli B
Explanation:
The multiplicity of infection (MOI) refers to the ratio between the numbers of viruses used to infect <em>E. coli</em> cells and the numbers of these <em>E. coli </em>cells. Benzer carried out several experiments in order to define the gene in regard to function. Benzer observed that <em>E. coli </em>strains with point mutations could be classified into two (2) complementary classes regarding coinfection using the restrictive strain as the host. With regard to his experiments, Benzer observed that rII1 and rII2 mutants (rapid lysis mutants) are complementary when they produce progeny after coinfect E. coli K (where neither mutant can lyse the host by itself). The rII group of mutants studied by Benzer does not produce plaques on <em>E. coli</em> K strains that carry phage λ (lysogenic for λ), but they produce plaques on <em>E. coli</em> B strains. This study showed that rIIA and rIIB are different genes and/or cistrons in the rII region.
Yes because the dominant genes would cover up the recessive ones
The correct answer is: D) Binding of the neurotransmitter causes chemically gated sodium channels to open in the motor end plate (junctional folds of the sarcolemma) and sodium enters the cell.
The motor neuron cell is connected to muscle cell via synaptic cleft, where neurotransmitter is released. The muscle side of this synapse is called motor end plate. Released neurotransmitter is acetylcholine and it binds to its receptor (ACh receptor) on the motor end plate. As it binds, ion channels open, and Na+ gets into the muscle cell. This event reduces the voltage difference between the inside and outside of the cell and causes depolarization which creates a wave through the entire muscle cell (its membrane-sarcolema). As a consequence, Ca2+ is released from the sarcoplasmic reticulum which will cause the contraction of the muscle cell.
