Answer:
the x^2 column would have a "22" between the 4 & 5
Step-by-step explanation:
x x^2
0 0
1 1
2 4
3 9
4 16
5 25
6 36
Answer:
1.
8x + 6y = 28
9x + 3y = 39
Set to equal y.
8x + 6y = 28
6y = -8x + 28
y = -8/6x + 28/6
y = -4/3x + 14/3
9x + 3y = 39
3y = -9x + 39
y = -9/3x + 39/3
y = -3x + 13
Set equal to each other.
-4/3x + 14/3 = -3x + 13
Combine like terms.
5/3x = 25/3
Multiply by 3/5
x = 5
Plug x in.
y = -3(5) + 13
y = -15 + 13
y = -2
(5, -2)
2.
-2x - 9y = -3
-7x - 9y= -33
Set equal to y.
-2x - 9y = -3
-9y = 2x - 3
y = -2/9x + 3/9
y = -2/9x + 1/3
-7x - 9y= -33
-9y = 7x - 33
y = -7/9x + 33/9
y = -7/9x + 11/3
Set equal to each other
-2/9x + 1/3 = -2/9x + 1/3
0 = 0
infinitely many solutions
Answer:
9 and 11
Step-by-step explanation:
So let's say that the first integer is x.
That means that the second integer is x+2, since it us the next odd number.
This problem can be easily solved with our mind the answer is 9 and 11, but I'll show you the steps to slove this.
We make an equation using these two numbers:

Now all we gotta do is solve for x:

Now we use either splitting the middle term or quadratic formula:

Now we split each terma and solve for x:

Now the question states <em>positive </em>so we can rule out x = -11.
Now we have the first integer x = 9,
the second integer is x+2 = 9+2 =11
So the two consecutive positive odd integers are 9 and 11