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3 years ago

Burn is to ointment as grief is to

Mathematics

1 answer:

Nitella [24]3 years ago

4 0

Answer:The answer is Sympathy

Step-by-step explanation:

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B. Determine the values of a and b so that f is continuous.<br><br> Please help!

wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

$\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to 4a-2b+3 = 4\\\\ \therefore \ \ 4a-2b = 1\\\\$

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

$\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\$

So,

$\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3$

$\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\$

In equation a multiply the by -2 and then add in the equation b:

$\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to -2b = -1\\\\ \to b = \frac{1}{2}$

So, the value of $a \ and \ b= \frac{1}{2}$

4 0

3 years ago

a compys quality control department found an average 5 defective models for every 1000 models that were checked. If the company

3241004551 [841]

The best thing to do is to found out the percentage that is faulty. 1% is equal to 10 faulty products, therefore, 0.5% is equal to 5. In order to out how many there are in 60,000, you need to simply multiply 5 by 60, which is 300. Therefore, 300 are faulty. Hope this helps :)

6 0

3 years ago

A company sells fruit cups in packs of 4. The packs currently weigh 20 oz. The company plans to reduce the weight of each cup by

skad [1K]

Answer:

4 ( 5 - n )

Step-by-step explanation:

The expression:

20 – 4n

Task: Rewrite the expression for the new weight as a product of two factors.

To do this we simply have to find the highest common factor (HCF) between 20 and 4n

20 = 4 * 5

4n = 4 * n

The HCF = 4

Expressing as a product of two factors;

4 ( 5 - n )

6 0

3 years ago

B) Mrs. Shakya sold a jewellery at a loss of 5%. If she had sold it at Rs 5,200 more,

Nadusha1986 [10]

Answer:

$\huge{ \fbox{ \sf{Rs \: 40000}}}$

Step-by-step explanation:

$\sf{Let \: CP \: ( \: cost \: price) \: be \: x}$

$\sf{Loss \: \% \: = 5 \% \: }$

$\sf{Selling \: price = CP \: - \: loss \: \% \: of \: CP}$

$\mapsto{ \sf x - \frac{5}{100} \times x}$

$\mapsto{ \sf{x - \frac{x}{20} }}$

$\mapsto{ \sf{ \frac{x \times 20 - x}{20} }}$

$\mapsto{ \sf{ \frac{20x - x}{20}}}$

$\mapsto{ \sf{ \frac{19x}{20}}}$

Now, Finding the New selling price

$\sf{New \: SP \: ( \: selling \: price)} = \frac{19x}{20} + 5200$

$\mapsto{ \sf{ \frac{19x + 5200 \times 20}{20}}}$

$\mapsto{ \sf{ \frac{19x + 10400}{20}}}$

Finally, finding the Cost price :

We have, Profit % = 8 %

$\sf{Cost \: price = Selling \: price \: - \: P\% \: of \: CP}$

$\mapsto{ \sf{x = \frac{19x + 104000}{20} - 8\% \: of \: x}}$

$\mapsto{ \sf{x = \frac{19x + 104000}{20} - \frac{8x}{100} }}$

$\mapsto{ \sf{x = \frac{19x + 104000}{20} - \frac{2x}{25} }}$

$\mapsto{ \sf{x = \frac{5(19x + 104000) - 2x \times 4}{100} }}$

$\mapsto{ \sf{x = \frac{95x + 520000 - 8x}{100} }}$

$\mapsto{ \sf{x = \frac{87x + 520000}{100}}}$

$\mapsto{ \sf{100x = 87x + 520000}} \: \: ( \sf{Cross \: multiplication}$

$\mapsto{ \sf{100x - 87x = 520000}}$

$\mapsto{ \sf{13x = 520000}}$

$\mapsto{ \sf{x = \frac{520000}{13}}}$

$\mapsto{ \boxed {\sf{x = 40000}}}$

Therefore, the cost price of the jewellery is Rs 40000

Hope I helped!

Best regards! :D

~ $\sf{TheAnimeGirl}$

5 0

3 years ago

use the discriminant to describe the roots of each equation. then select the best description. x2 9x 14 = 0

Jobisdone [24]

Discriminant = b^2 - 4ac; where a = 1, b = 9 and c = 14
d = (9)^2 - 4(1)(14)
d = 81 - 56
d = 25

the discriminant is greater than zero, so there are two real roots

4 0

3 years ago