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Sonja [21]
3 years ago
13

Find (f^-1)'(a): f(x) = 3+x^2+tan(pi(x)/2), -1

Mathematics
1 answer:
Slav-nsk [51]3 years ago
4 0
(f^-1)'(a)=1/f'(f^-1)'(a)
f(a) =3 = 3+x^2+tan(pi(x)/2), 
0= 3+x^2+tan(pi(x)/2)
<span>(f^-1)'(a)
= 1/[f ' ( f^-1(a) )] (f^-1)'(3)
 = 1/[f ' ( f^-1(3) )] (f^-1)'(3)
 = 1/[f ' ( 0 )] (f^-1)'(3)
</span>=0+1/2pie(1)
=pi/2
hope it helps
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<h3>What does summation mean in math?</h3>

The outcome of adding numbers or quantities mathematically is a summation, often known as a sum. A summation always has an even number of terms in it. There may be just two terms, or there may be 100, 1000, or even a million. Some summations include an infinite number of terms.

<h3>Briefing:</h3>

Distribute 2j to (j+3).

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Evaluate each summation using properties or formulas from the lesson.

The lower index is 1, so any properties can be used.

The sum is 5,494,000.

<h3>Calculation according to the statement:</h3>

\sum_{j=1}^{200} 2 j(j+3)

simplifying them we get:

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Split the summation into smaller summations that fit the summation rules.

\sum_{j=1}^{200} 2 j^{2}+6 j=2 \sum_{j=1}^{200} j^{2}+6 \sum_{j=1}^{200} j

\text { Evaluate } 2 \sum_{j=1}^{200} j^{2}

The formula for the summation of a polynomial with degree 2

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\sum_{k=1}^{n} k^{2}=\frac{n(n+1)(2 n+1)}{6}

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(2)$$\left(\frac{200(200+1)(2 \cdot 200+1)}{6}\right)$$

we get: 5373400

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5373400 + 120600

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The sum of the equation is  = 5494000.

To know more about  summations visit:

brainly.com/question/16679150

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