Question

A crate is dragged up a ramp at constant speed. The work done on the system can be accounted for by:

Answer 1

Answer:

The work done on the system can be accounted for by;

Both $E_g$ and $E_{int}$

Explanation:

The speed of the crate = Constant

Therefore, the acceleration of the crate = 0 m/s²

The net force applied to the crate, $F_{NET}$ = 0

Therefore, the force of with which the crate is pulled = The force resisting the upward motion of the crate

However, we have;

The force resisting the upward motion of the crate = The weight of the crate + The frictional resistance of the ramp due to the surface contact between the ramp and the crate

The work done on the system = The energy to balance the resisting force = The weight of the crate × The height the crate is raised + The heat generated as internal energy to the system

The weight of the crate × The height the crate is raised = Gravitational Potential Energy = $E_g$

The heat generated as internal energy to the system = $E_{int}$

Therefore;

The work done on the system = $E_g$ + $E_{int}$.