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gtnhenbr [62]
3 years ago
6

25) A 10 kg box is sitting on a shelf 15 feet in the air. How could you increase the potential energy of the box? (check all tha

t apply)  Raise the box to 20 feet.  Lower the box to 10 feet  Increase the mass of the box to 15 kg  Decrease the bass of the box to 5 kg  Drop the box off of the shelf.
Physics
1 answer:
irakobra [83]3 years ago
7 0
Potential energy is the energy possessed by a body or an object while at rest while kinetic energy is the energy while the body is at motion.
Potential energy is given by Mgh where m is the mass of the object, g is the gravitational acceleration (a constant) and h is the height.
Therefore, potential energy varies directly proportional to the mass of the object and the height.
Thus in this case, an increase in the mass of the box by 15 kg and raising the height of the box by 20 feet, will result to an increase in potential energy of the box.
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In a physics lab, Asha is given a 10.7 kg uniform rectangular plate with edge lengths 67.3 cm by 53.5 cm . Her lab instructor re
Leya [2.2K]

Answer:

I=2.6363\ kg.m^2

Explanation:

Given:

dimension of uniform plate, (0.673\times 0.535)\ m^2

mass of plate, m=10.7\ kg

Now we find the moment of inertia about the center of mass of the rectangular plate is given as:

I_{cm}=\frac{1}{12} \times m(L^2+B^2)

where:

L= length of the plate

B= breadth of the plate

I_{cm}=\frac{1}{12} \times 10.7\times(0.673^2+0.535^2)

I_{cm}=0.6591\ kg.m^2

We know that the center of mass of the rectangular plane is at its geometric center which is parallel to the desired axis XX' .

Now we find the distance between the center of mass and the corner:

s=\frac{\sqrt{ (0.673^2+0.535^2)}}{2}

s=0.4299\ m

Now using parallel axis theorem:

I=I_{cm}+m.s^2

I=0.6591+10.7\times 0.4299^2

I=2.6363\ kg.m^2

6 0
3 years ago
A boy kicks a soccer ball, giving it an initial speed of 7.5m/s at an angle of 27° above the horizontal(=ground). How high will
Gelneren [198K]

When the initial speed given is 7.5m/s at an angle of 27° , ball will go

4.637 meters.

Assume no air opposition to the ball ;

Vertical component of ball is sin 27° =  0.453

0.453* 7.5 = 3.404 meters /sec

Time taken to reach ground is :

3.404 = -3.404+9.8*t

t= 6.808/9.8= 0.694 sec

Horizontal component is 7.5*cos27°= 6.682m/s

Distance = speed * time

=6.682 * 0.694

=4.637 meters

Horizontal distance it can cover in 0.694 sec is 4.637 meters

So range of ball is 4.637 meters.

Form of motion experienced by an object or particle that is projected near surface of the earth and moves along a curve is called Projectile motion. Three types of projectile motion are Horizontal projectile motion. Oblique projectile motion and Projectile motion on an inclined plane.

To know more about projectile motion, refer

brainly.com/question/24216590

#SPJ13

3 0
1 year ago
The period (T) of an oscillating wave is 1/5s. What happens to the frequency (f) of the wave if T increases to 1/2s
Anastasy [175]
Frequency = 1/T
as the 5 is reduced, frequency is increase.
as 1 whole wave travels through a point in a lesser time now
6 0
3 years ago
The law of reflection states that if the angle of incidence is 19 degrees, the angle of reflection is ___ degrees.
Wewaii [24]
using the law of refraction, the incidence is equal to the reflection, but not refraction
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3 years ago
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Sediment forms through _______________________ of rocks,
Anna71 [15]

Answer:

C

Explanation:

7 0
3 years ago
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