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3 years ago

Why do covalent and ionic bonds form?

Physics

1 answer:

nevsk [136]3 years ago

5 0

Answer:

Ionic bonds form when a nonmetal and a metal exchange electrons, while covalent bonds form when electrons are shared between two nonmetals. An ionic bond is a type of chemical bond formed through an electrostatic attraction between two oppositely charged ions.

Explanation:

hope this helps!

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An object of mass 0.50 kg is transported to the surface of Planet X where the object's weight is measured to be 20 N. The radius

vovangra [49]

Explanation:

The free fall acceleration is:

F = ma

20 N = (0.50 kg) a

a = 40 m/s²

The mass of Planet X is:

F = GMm / r²

20 N = (6.67×10⁻¹¹ Nm²/kg²) M (0.50 kg) / (4.0×10⁶ m)²

M = 9.6×10²⁴ kg

5 0

3 years ago

PLEASE HELLPPP ITS FIR A FINAL 3.Speed (v) abs wavelength ( λ ) and the frequency (f) of sound are related asRequired to answer.

Aliun [14]

Answer:

B. v = λ X f

<em><u>Hope this helps! </u></em>

8 0

3 years ago

The Bohr model of the hydrogen atom pictures the electron as a tiny particle moving in a circular orbit about a stationary proto

igor_vitrenko [27]

a) The angular velocity of the electron is $4.12\cdot 10^{16} rad/s$

b) The number of revolutions per second is $6.54\cdot 10^{15}$ rev/s

c) The centripetal acceleration of the electron is $8.98\cdot 10^{22} m/s^2$

Explanation:

This is a problem of uniform circular motion: in fact, the electron orbits around the proton in a uniform circular motion.

The angular velocity of an object in uniform circular motion is given by

$\omega = \frac{v}{r}$

where

v is the linear speed

r is the radius of the trajectory

For the electron orbiting around the proton, we have

$v=2.18 \cdot 10^6 m/s$

$r=5.29\cdot 10^{-11} m$

Therefore, the angular velocity is

$\omega=\frac{2.18\cdot 10^6}{5.29\cdot 10^{-11}}=4.12\cdot 10^{16} rad/s$

The period of revolution of the electron is given by

$T=\frac{2\pi}{\omega}$

where

$\omega = 4.12\cdot 10^{16}rad/s$ is the angular velocity

Substituting,

$T=\frac{2\pi}{4.12\cdot 10^{16}}=1.53\cdot 10^{-16}s$

The period is the time the electron takes to make one complete orbit around the proton; therefore, the number of revolutions of the electrons in one second is:

$f=\frac{1}{T}=\frac{1}{1.53\cdot 10^{-16}}=6.54\cdot 10^{15}$ rev/s