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2 years ago

How long must a pendulum be to have a period of 4.6 5 on Neptune, where g = 11.15 m/s?

Physics

1 answer:

Anon25 [30]2 years ago

5 0

Answer:

5.98 m

Explanation:

$T=2\pi \sqrt\frac{L}{g}$

$T^2=4\pi ^2L/g\\L = gT^2/(4\pi^2)$ = 11.15*4.6²/(4π²) = 5.98 m

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2 years ago

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3 years ago

Two students are on a balcony 19.1 m above the street. One student throws a ball, b1, vertically downward at 13.9 m/s. At the sa

tester [92]

Answer:

Part a)

$t = 2.83 s$

Part b)

Ball thrown downwards = $v_f = 23.8 m/s$

Ball thrown upwards = $v_f = 23.8 m/s$

Part c)

$d = 22.24 m$

Explanation:

Part a)

Since both the balls are projected with same speed in opposite directions

So here the time difference is the time for which the ball projected upward will move up and come back at the same point of projection

Afterwards the motion will be same as the first ball which is projected downwards

so here the time difference is given as

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$t = 2.83 s$

Part b)

Since the displacement in y direction for two balls is same as well as the the initial speed is also same so final speed is also same for both the balls

so it is given as

$v_f^2 - v_i^2 = 2 a \Delta y$

$v_f^2 - (13.9)^2 = (2)(-9.81)(-19.1)$

$v_f^2 = 567.9$

$v_f = 23.8 m/s$

Part c)

Relative speed of two balls is given as

$v_{12} = v_1 - v_2$

$v_{12} = (13.9) - (-13.9) = 27.8 m/s$

now the distance between two balls in 0.8 s is given as

$d = v_{12} t$

$d = 27.8 \times 0.8$

$d = 22.24 m$

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3 years ago

A football player runs 20 meters North of a football field, and then 15 meters East. The total motion lasted 15 seconds. What wa

vlada-n [284]

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3 years ago

How long must a pendulum be to have a period of 4.6 5 on Neptune, where g = 11.15 m/s?​

How long must a pendulum be to have a period of 4.6 5 on Neptune, where g = 11.15 m/s?