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nasty-shy [4]
3 years ago
7

A bit confused on what to do. Can someone help?

Mathematics
1 answer:
Allisa [31]3 years ago
4 0

Answer: the answer is on a calculator

Step-by-step explanation:

If your aboe to do that you can so anything

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Every year, the amount of CO2 in the atmosphere increases by a factor of
MrRa [10]
About 0.5 percent per year
8 0
3 years ago
Need help on this math problem​
erik [133]

Answer:

-5, 18, \sqrt{13}

Step-by-step explanation:

We can solve the first equation, f of -3. The value of the function f is \frac{1+x^2}{x+1}, and plugging in -3 gets us \frac{1+9}{1-3}, this results in 10 divided by negative 2, which is negative 5.

Now, we must solve g of negative one third. The function g is defined as |9x-15|. Plugging in negative one third into the question gets us |9(-\frac{1}{3})-15|

9 times negative one third is -3, and -3 minus 15 is -18. The absolute value of -18 is 18.

Now, we must solve h of negative 2, and h is defined as \sqrt{-3-8x}. Plugging in negative 2, we have \sqrt{-3-8(-2)}. Negative 8 times negative 2 is positive 16, and 16 minus 3 is 13. The answer is the square root of 13

7 0
2 years ago
Apr 24,8:28:53 AM<br> Find the 98th term of the arithmetic sequence -10,-8, -6, ...
Nata [24]

Answer: 184

Step-by-step explanation:

The nth term of am arithmetic sequence is calculated as:

Nth term= a+(n-1)d

where a = first term

d = common difference

a = -10

d = -8 -(-10) = -8+10 = 2

98th term= a+(n-1)d

= -10 + (98-1)(2)

= -10 + (97×2)

= -10 + 194

= 184

The 98th term of the arithmetic sequence is 184

6 0
3 years ago
A 500 g model train car traveling at 0.8 m/s collides with a 300 g stationary car. The cars hook up and move off down the track
sdas [7]

Answer:

0.5ms^{-1}

Step-by-step explanation:

Let v be the speed after the collision of both the cars.

Now, momentum is given by: mass × velocity, then by equating the total momentum before and after the collision of the two cars, we get

500{\times}0.8+300{\times}0=(500+300)v

⇒400+0=800v

⇒400=800v

⇒v=0.5ms^{-1}

Thus, they are moving at the velocity of 0.5ms^{-1}

3 0
3 years ago
Read 2 more answers
I don’t know how to do this for nothing
Vadim26 [7]

Answer:

ok

Step-by-step explanation:

4 0
2 years ago
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