Answer:
1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle
Step-by-step explanation:
Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is
V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³
the mass in that volume would be m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)
The density of an alpha particle is ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be
ρ= m/V
since both should be equal ρ=ρa , then
ρa= m/V =N*L/V → N =ρa*V/L
replacing values
N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg = 1.544*10⁹ Linebackers
N=1.544*10⁹ Linebackers
Answer:
![\[y=-2x+13\]](https://tex.z-dn.net/?f=%5C%5By%3D-2x%2B13%5C%5D)
Step-by-step explanation:
Equation of the line CD is given as ![\[y=-2x-2\]](https://tex.z-dn.net/?f=%5C%5By%3D-2x-2%5C%5D)
Slope of the line CD = -2
Slope of the line parallel to CD = -2
Equation of the line parallel to CD is given by ![\[y=mx+c\]](https://tex.z-dn.net/?f=%5C%5By%3Dmx%2Bc%5C%5D)
![\[y=-2x+c\]](https://tex.z-dn.net/?f=%5C%5By%3D-2x%2Bc%5C%5D)
But this line passes through (4,5)
Substituting the values in the equation:
![\[5=-2*(4)+c\]](https://tex.z-dn.net/?f=%5C%5B5%3D-2%2A%284%29%2Bc%5C%5D)
=> ![\[c=5+8=13\]](https://tex.z-dn.net/?f=%5C%5Bc%3D5%2B8%3D13%5C%5D)
So the overall equation of the parallel line is given by
Answer(-2, -1)
Step-by-step explanation:
I guessed and got it right.
Answer:
hi
Step-by-step explanation:
i think it is A
because
hope it helps
have a nice day
I would assume that you would subtract 40 from 60 and get 20. (60-40=20) So I'd say 20 hours.
