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docker41 [41]
3 years ago
13

Una llave de tuercas de 0.5kg cae desde una altura de 10m.¿Cual es su cantidad de movimiento inmediato antes de tocar el suelo?

Physics
1 answer:
Anna35 [415]3 years ago
4 0

Answer:

<u><em> </em></u>La cantidad de movimiento de la llave de tuercas es 7 kg*m/s

Explanation:

Un cuerpo realiza un movimiento rectilíneo uniformemente acelerado (m.r.u.a.) omovimiento rectilíneo uniformemente variado (m.r.u.v.) cuando su trayectoria es una línea recta y su aceleración es constante, de manera que la velocidad aumenta o disminuye su módulo de manera uniforme.

En este tipo de movimiento, en ocasiones resulta útil tener en cuenta la siguiente expresión:

v²= vo² + 2*a*x

donde v es la velocidad, v0 es la velocidad inicial, a es la aceleración y x la posición.

En este caso, la llave cae con m.r.u.v, siendo los datos:

  • vo= 0
  • a= gravedad g
  • x=10 m

Entonces:

v²= 2*g*x

v=√2*g*x

v=√(2*9,80*10)

v=  14 m/s

La cantidad de movimiento o momento lineal es una magnitud que relaciona la masa y velocidad de un cuerpo mediante la expresión:

p= m*v

Siendo m= 0.5 kg y v=14 m/s, la cantidad de movimiento en este caso es:

p = 0,5 kg . 14 m/s

p= 7 kg*m/s

<em><u>La cantidad de movimiento de la llave de tuercas es 7 kg*m/s</u></em>

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