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Elanso [62]
3 years ago
6

Help please !! physics kinematic equations

Physics
1 answer:
jarptica [38.1K]3 years ago
7 0

Explanation:

A or E I think cous I use to do this in yr 7

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URGENT!!!! WILL GIVE BRAINLIEST!!!!!! 15 POINTS
Artyom0805 [142]
It's the angle made by the incident ray when it's perpendicular to the surface. (Perpendicular lines are the lines that form a graph or like a 90-degree angle)
3 0
3 years ago
Read 2 more answers
If opposing forces acting on an object are equal, the net force is
makkiz [27]

Answer:

0 N

Explanation:

suppose, you push a box with 5 N, and another person pushes the box on the opposite side of the box with 5 N, the net force (resultant ) is 0 N, the box will not move if it wasn't moving

hope this helps

8 0
2 years ago
At t=0 a ball is projected vertically upward from a roof of a building of height 68.1 meters with a velocity of 42.4 m/s. The ba
Finger [1]

Answer:

7.45 s.

Explanation:

Given:

h = 68.1 m

vi = 0 m/s

vf = 42.4 m/s

g = 9.81 m/s^2

Using,

h = vi*t +1/2*(a*t^2)

68.1 = 1/2 * (9.81*t^2)

t = sqrt((68.1*2)/9.81)

= 3.726 s.

Total time of flight = 2*t

= 2 * 3.726

= 7.45 s.

4 0
3 years ago
Read 2 more answers
When a flat slab of transparent material is placed under water, the critical angle for light traveling from the slab into water
Novosadov [1.4K]

Answer:

(a) 40.6 degree

Explanation:

When refraction takes place from slab to water, the critical angle is 60 degree.

Use Snell's law

refractive index of water with respect to slab

\mu _{w}^{s}=\frac{Sin60}{Sin90}

\frac{\mu _{w}}{\mu _{s}}=0.866

\frac{1.33}{\mu _{s}}=0.866

μs = 1.536

Now for slab air interface, the critical angle is C.

\mu _{a}^{s}=\frac{SinC}{Sin90}

\frac{\mu _{a}}{\mu _{s}}=\frac{SinC}{Sin90}

1 / 1.536 = Sin C

C = 40.6 degree

3 0
3 years ago
A U-shaped tube, open to the air on both ends, contains mercury. Water is poured into the left arm until the water column is 10.
Masja [62]

Answer:

0.368 cm

Explanation:

x = distance by which the mercury rise

d = depth of the water = 10 cm = 0.10 m

ρ = density of water = 1000 kgm⁻³

ρ' = density of mercury = 13600 kgm⁻³

P₀ = atmospheric pressure

Using equilibrium of pressure on both side

P₀ + ρ g d = P₀ + ρ' g (2x)

(1000) (0.10) = (13600) (2x)

x = 0.00368 m

x = 0.368 cm

8 0
3 years ago
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