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alisha [4.7K]
3 years ago
6

I’m about to die of cuteness overload Naruto, sasuke, sakura, and Kakashi-sensei

Chemistry
2 answers:
Gnoma [55]3 years ago
7 0

Answer:

dfadskjfkhasdljkfasdhfaljksfh so cuttttteeee :3

;w;""'

vlabodo [156]3 years ago
6 0
I am so glad i have now seen this picture. my life is now complete
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A 50.00 g sample of an unknown metal is heated to 45.00°C. It is then placed in a coffee-cup calorimeter filled with water. The
True [87]
First, in order to calculate the specific heat capacity of the metal in help in identifying it, we must find the heat absorbed by the calorimeter using:
Energy = mass * specific heat capacity * change in temperature
Q = 250 * 1.035 * (11.08 - 10)
Q = 279.45 cal/g

Next, we use the same formula for the metal as the heat absorbed by the calorimeter is equal to the heal released by the metal.

-279.45 = 50 * c * (11.08 - 45) [minus sign added as energy released]
c = 0.165

The specific heat capacity of the metal is 0.165 cal/gC
6 0
2 years ago
Read 2 more answers
!!!Need answer for chem homework ASAP PLS !!!!
stealth61 [152]

Answer:

The answer to your question is: kc = 6.48

Explanation:

Data

             Given                 Molecular weight

CaO =    44.6 g                    56 g

CO₂ =     26 g                       44 g

CaCO₃ = 42.3 g                  100 g

Find moles

        CaO                 56 g ----------------  1 mol

                                 44.6 g --------------   x

                               x = (44.6 x 1) / 56 = 0.8 mol

        CO₂                 44 g -----------------  1 mol

                                26 g ----------------    x

                               x = (26 x 1 ) / 44 = 0.6  moles

        CaCO₃            100 g ---------------   1 mol

                                42.3g --------------    x

                              x = (42.3 x 1) / 100 = 0.423 moles

       

Concentrations

 

        CaO     =    0.8 / 6.5  = 0.12 M

         CO₂    =     0.6 / 6.5 = 0.09 M

        CaCO₃  =   0.423 / 6.5 = 0.07 M

Equilibrium constant =   \frac{[products]}{[reactants]}

Kc = [0.07] / [[0.12][0.09]

Kc = 0.07 / 0.0108

kc = 6.48

7 0
3 years ago
2 . what is the formula weight of (nh4)2so4? 118 amu 116 amu 100 amu 132 amu
Nataly [62]
Hey there!

(NH₄)₂SO₄ = 14 * 2 + 1 * 8 + 32+ 16 * 4 => 132 amu


6 0
3 years ago
What is Gibbs free energy
Alenkinab [10]

Answer:

The minimum amount of energy needed the the cell to perform various cellular,biochemical and physiological activities is known is Gibbs free energy.

Explanation:

The change in gibbs free energy of is very much important to determine whether a given reaction is spontaneous,non spontaneous  or equilibrium.

 1 If gibbs free energy change of a reaction is negative then the reaction is spontaneous.

2  If the free energy change is 0 then the reaction is in equilibrium stage.

3  If free energy change is positive then the reaction is non spontaneous.

4 0
2 years ago
ATOMS: MULTIPLE CHOICE
loris [4]

Answer:

Double bonds. It says I have to write more words lol but yeah it's double bonds

4 0
2 years ago
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