1) Chemical formula for propane is CH₃-CH₂-CH₃.
Propane is a three carbon alkane (acyclic saturated <span>hydrocarbon).
</span>2) Chemical formula for propanal is CH₃-CH₂-CH=O.
Propanal <span> is a </span>saturated<span> three carbon </span>aldehyde (have<span> a </span>carbonyl<span> center).
3) </span>Chemical formula for propanol is CH₃-CH₂-CH₂-OH.
1-propanol <span> is a </span><span>primary alcohol.
4) </span>Chemical formula for propanone is (CH₃)₂-C=O.
Propanone or acetone is <span>he simplest and smallest</span> ketone.
Answer: a) The concentration after 8.8min is 0.17 M
b) Time taken for the concentration of cyclopropane to decrease from 0.25M to 0.15M is 687 seconds.
Explanation:
Expression for rate law for first order kinetics is given by:

where,
k = rate constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
a) concentration after 8.8 min:



b) for concentration to decrease from 0.25M to 0.15M


KE = 0
<h3>Further explanation </h3>
Energy is the ability to do work
Energy because its motion is expressed as Kinetic energy (KE) which can be formulated as:

So for two objects that have the same speed, the greater the mass of the object, the greater the kinetic energy
The stone in hand is in a motionless state (at rest) so that its velocity (v) = 0, so it has no kinetic energy
But this stone can have <em>potential energy that is gained due to its height</em>
Answer:
D) is the answer please thanks